All categories

3 years ago

Help pls!!!!!

Mathematics

2 answers:

OLEGan [10]3 years ago

7 0

Answer:

Option D, y ≥ 5x + (-3)

Step-by-step explanation:

Step 1: Make an expression

The value of y is greater than or equal to the sum of five times the value of x and negative three.

The value of y is greater than or equal to ← y ≥

The sum of five times the value of x and negative three ← 5x + (-3)

y ≥ 5x + (-3)

Answer: Option D, y ≥ 5x + (-3)

Inga [223]3 years ago

6 0

Answer:

y ≥ 5x+ (-3)

Step-by-step explanation:

greater than or equal to ≥

The sum means add

y ≥ 5x+ (-3)

You might be interested in

Also need help on this

Ira Lisetskai [31]

Answer is 0.5
-2 divided by -4 equals 0.5
and same thing for the rest of the equation.

8 0

3 years ago

Read 2 more answers

Evaluate the expression 2x - 5 when x = -5 C) 5 D) 15 A)-5 B) -15

IRINA_888 [86]

Answer:

B) -15

Step-by-step explanation:

8 0

3 years ago

Select the correct ratios.

Goshia [24]

65:100 because there are 65 girls and then 65 girls + 35 boys = 100 total students

4 0

2 years ago

Implicit differentiation Please help

Anvisha [2.4K]

Answer:

$y''(-1) =8$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Product Rule/Basic Power Rule]: $-y - xy' - 2y' = 0$
[Algebra] Isolate y' terms: $-xy' - 2y' = y$
[Algebra] Factor y': $y'(-x - 2) = y$
[Algebra] Isolate y': $y' = \frac{y}{-x-2}$
[Algebra] Rewrite: $y' = \frac{-y}{x+2}$

Step 3: Find y

Define equation: $-xy - 2y = -4$
Factor y: $y(-x - 2) = -4$
Isolate y: $y = \frac{-4}{-x-2}$
Simplify: $y = \frac{4}{x+2}$

Step 4: Rewrite 1st Derivative

[Algebra] Substitute in y: $y' = \frac{-\frac{4}{x+2} }{x+2}$
[Algebra] Simplify: $y' = \frac{-4}{(x+2)^2}$

Step 5: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}$
[Derivative] Simplify: $y'' = \frac{8}{(x+2)^3}$

Step 6: Find Slope at Given Point

[Algebra] Substitute in x: $y''(-1) = \frac{8}{(-1+2)^3}$
[Algebra] Evaluate: $y''(-1) =8$

6 0

3 years ago

Read 2 more answers

Juan scored 15 points more on this test than

maw [93]

Juan's least integer scores in both tests will be 85 and 100 respectively.

Test average of his two scores is atleast 92

Let :

Score on test 1 = b
Score on test 2 = b + 15

Average score can be related thus:

(Sum of score ÷ number of test) ≥ 92
(b + b + 15) ÷ 2 ≥ 92
(2b + 15) ÷ 2 = 92
2b + 15 = 184
2b = 184 - 15
2b = 169
b = 169 ÷ 2
b = 84.5

Therefore, since both scores are integers, his least scores on both tests will be ::

85 and (85 + 15) = 100

Learn more :brainly.com/question/15528814

8 0

3 years ago