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Goryan [66]
2 years ago
6

Find the median, first quartile, third quartile, and interquartile range of the data.

Mathematics
1 answer:
vovangra [49]2 years ago
8 0

Answer:

Median: 88, First Quartile: 84, Third Quartile: 92, IQR (interquartile range): 8

Step-by-step explanation:

1. Sort the numbers in numerical order (like 1, 2, 3, etc.)

2. Find the number that is in the middle

3. Find all the quartiles by finding the median of the lower and upper halves of the list

4. Subtract Q1 (quartile 1) and Q3 (quartile 3) like this: Q3 - Q1 to get IQR

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Someone please help!
igomit [66]

Answer:

-11/12 make sure you press the negative

8 0
3 years ago
If alpha beta are the roots of the equation
Vikki [24]

Answer:

Step-by-step explanation:

Hello, I believe that we can consider a different from 0.

By definition of the roots we can write.

ax^2+bx+c=a(x-\alpha)(x-\beta)=a(x^2-(\alpha + \beta)x+\alpha \cdot \beta)\\\\\text{So we can say that:}\\\\\alpha + \beta = \dfrac{-b}{a}\\\\\alpha \cdot \beta=\dfrac{c}{a}\\\\\text{So the expected quadratic equation is}\\\\(x+\dfrac{b}{a})(x-\dfrac{c}{a})=0\\\\ \Large \boxed{\sf \bf \ (ax+b)(ax-c)=0 \ }

Thank you

8 0
3 years ago
PLEASE HELP! <br> Find x - y less than 0.<br> A. - y - x<br> B. x - y<br> C. - x + y
notka56 [123]
The answer is c) - x + y
4 0
3 years ago
How to find the hypothesis
Kaylis [27]

Answer:

You dont need to

Step-by-step explanation:

A hypothesis is just a guess, so you cant be wrong

5 0
3 years ago
Read 2 more answers
What is the surface area of the figure shown? (Use 3.14 for π.)
Ivanshal [37]
We know that
Part 1) 
[surface area of a cone without base]=<span>π*r*l
r=3 in
l=slant height ----> 6 in
</span>[surface area of a cone without base]=π*3*6------> 56.52 in²

[surface area of a cylinder]=π*r²+2*π*r*h------> only one base
r=3 in
h=5 in
[surface area of a cylinder]=π*r²+2*π*r*h
[surface area of a cylinder]=π*3²+2*π*3*5-----> 122.46 in²

[surface area of the composite figure]=56.52+122.46-----> 178.98 in²

the answer Part A) is
 178.98 in²

Part B) 
[surface area of the composite figure]
=12*16+2*12*7+2*16*7+5*12+5*16+13*16----> 932 ft²

the answer Part B) is 
 932 ft²



4 0
4 years ago
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