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1 year ago

Over the last 16 years Johanna saved some of her pay each month. She now has $46000. She decided to invest some of it at 5.25%

Mathematics

1 answer:

goldfiish [28.3K]1 year ago

6 0

Answer:

what is the question?

do you have to find how much she is investing?

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None shows the answer

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3 years ago

You take a bite of a cookie and begin to crush it between your teeth making smaller bits in your mouth.

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Physical, you aren't changing the substance, you are just changing the shape of the cookie

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3 years ago

A woman received 5 per cent interest on a loan of $300 for 1 year. How much interest did she receive? $5 $15 $30 $150 none of th

choli [55]

Answer:

15$

Step-by-step explanation:

this is because if you use our formula of I= prt

we can substitute our varibles for our equation

I= 300 x 0.05 x 1

we turn 5 in 0.05 to represent out rate, due to this our rate would have to be Simplified into a percent then a decimal

after this if we now proceed through our equation we will get

I = 300 x 0.05 x 1

I = 15

6 0

3 years ago

Bradford Electric Illuminating Company is studying the relationship between kilowatt-hours (thousands) used and the number of ro

slamgirl [31]

For the regression equation and e the number of kilowatt-hours, in thousands, for a six-room house is mathematically given as

Y = 1.33-0.667X and 5.3332

<h3>What is the number of kilowatt-hours, in thousands, for a six-room house?</h3>

Generally, the equation for the standard deviation is mathematically given as

$s$ ₓ = $\sqrt{\frac{\sum\(X-\=X)^2}{n-1} }$

= $\sqrt{\frac{66.9}{10-1} }$

= 2.72

$s_y$ = $\sqrt{\frac{36.4}{10-1} }$

= 2.01

therefore correlation coff

r = $\frac{44.6}{(10-1)(2.72)(2.01)}$

r = 0.9038

In conclusion the regression equation is given

b = r_sy/sx

b = (0.9038)(2.01/2.72)

= 0.667

intercept

a = 7.4-0.667(9.1)

a = 1.33

The regression equation is

Y = 1.33-0.667X

(b) number of kilowatts x = 6 house

Y = 1.33-0.667X

Y = 1.33-0.667(6)

= 5.3332