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3 years ago

If your teacher tells you to questions 38 through 51 in your math book for homework ,how many questions is that ?

Mathematics

2 answers:

eduard3 years ago

8 0

That would be 13 questions!

Taya2010 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

its 13 just subtract 38 from 51 and u got 13

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aniked [119]

Answer:

I think C. is it

Step-by-step explanation:

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3 years ago

Cuanto es dcneicneen eie neim

svetlana [45]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Item cost $430 before taxes and the sales tax is $38.70 find a sales tax

natulia [17]

Answer:

sales tax= 9 %

Step-by-step explanation:

sales tax= cost x %tax

38.70 = 430 x %tax

%tax = 38.7/430 = 0.09 = 9 %

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3 years ago

Please solve this it’s due in 2 hours I’ll give brainliest ONLY ANSWER IF YOU KNOW

Vsevolod [243]

Answer:

All are positive, and point upwards. The angle that they increase along the horizontal axis is different.

Step-by-step explanation:

There are no negative signs that the x is multiplied in any of the equations, and the number they are multiplied by is different for each graph: one is 1, another is 2, and the last is 3.

6 0

3 years ago

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$