Answer:
16π
Step-by-step explanation:
Given that:
The sphere of the radius = 


The partial derivatives of 

Similarly;

∴




Now; the region R = x² + y² = 12
Let;
x = rcosθ = x; x varies from 0 to 2π
y = rsinθ = y; y varies from 0 to 
dA = rdrdθ
∴
The surface area 



![= 2 \pi \times 4 \Bigg [ \dfrac{\sqrt{16-r^2}}{\dfrac{1}{2}(-2)} \Bigg]^{\sqrt{12}}_{0}](https://tex.z-dn.net/?f=%3D%202%20%5Cpi%20%5Ctimes%204%20%5CBigg%20%5B%20%5Cdfrac%7B%5Csqrt%7B16-r%5E2%7D%7D%7B%5Cdfrac%7B1%7D%7B2%7D%28-2%29%7D%20%5CBigg%5D%5E%7B%5Csqrt%7B12%7D%7D_%7B0%7D)

= 8π ( -2 + 4)
= 8π(2)
= 16π
63$
five hours = 45$
1 hour = 9$
7 hours = 63$
The closest marks on the ruler that was used to make a measurement of 23.435m is 0.01m apart.
<h3>What is a Ruler?</h3>
This refers to a tool which is used to measure distances of two points or area and has standard markings.
Since the thousandth digit is uncertain and the significant figures are digits which are read from the measuring instrument plus one doubtful number on the ruler then the most appropriate choice will be 0.01m.
Read more about Ruler here brainly.com/question/18558504
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The Y-int would be <u>-16</u>
Uhm what? sir your asking a question, and not giving someone else an answer