12 would be the unit rate you mulitply 3 × 4
Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
Answer:
B. 4.05 liters
Step-by-step explanation:
So hmm check the picture below
what's the width? well, w = l + 3