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2 years ago

6

Find the slope and the line between each pair of points

1 answer:

dalvyx [7]2 years ago

4 0

Girl what are you talking about

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If 1 kg = 2.2 pounds, convert 77 kg into pounds

weqwewe [10]

Answer:

169.4 lbs

Step-by-step explanation:

77 * 2.2 = 169.4

5 0

3 years ago

Read 2 more answers

There are two drama classesoffered at a middle school. The 8th grade class has 13 fewer students than the 7th grade class. If th

Eddi Din [679]

Answer:

Class 8 has 27 and class 7 has 40

Step-by-step explanation:

8th (r) class has 13 fewer than 7th (x).
x -13 = r

Total for both classes = 67

r + x - 13 = 67
r + x = 80

80 divided by two = 40 (per class)

40 - 13 = 27

4 0

2 years ago

PLEASE HELP MY TEACHER WON'T RESPOND AND EVERYONE IS BUSY!!

Zolol [24]

is this like a page?Step-by-step explanation:

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3 years ago

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the<br> function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

<u>Then, the minimum point of this function is (3,1) and it corresponds to (A)</u>

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

<u>Then, the minimum point of this function is (0,1) and it corresponds to (C)</u>

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

<u>Then, the minimum point of this function is (2,3) and it corresponds to (B)</u>

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

<u>Then, the minimum point of this function is (2,-2) and it corresponds to (D)</u>

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I hope it helps you!

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8 0

3 years ago

Rename 1/2 and 1/5 using the least common denominator.

gladu [14]

C multiply 1/2 by 10 and 1/5 by 2

3 0

3 years ago