I think it's true but I'm not sure about that
If 
is a number that is both divisible by 4 and 5, then
4 and 5 are coprime, so we can use the Chinese remainder theorem to solve this system and find that 
is a solution to the system, where 
is any integer. Simply put, any multiple of 20 fits the bill.
Now, there are 11 numbers between 100 and 300 that are divisible by 20 (100, 120, 140, and so on). We have 
when 
, so the sum we want to compute is
First, you plug your given values in. Since x is 1.5, it will be multiples by 2x to get 3.2. Since y is -3, it will be added to 1 to get -2. Finally, the two are multiplied together to get -6.4 if I am correct.
Answer:
3*( 8-2n)=5n
The number is 24/11
Step-by-step explanation:
three times
3*
the difference of eight and twice a number
3*( 8-2n)
is five times the number
3*( 8-2n)=5n
To solve
Distribute
3*8 -3*2n = 5n
24 -6n = 5n
Add 6n to each side
24 - 6n +6n = 5n +6n
24 = 11n
Divide each side by 11
24/11 = 11n/11
24/11 =n
The number is 24/11
