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3 years ago

Shay makes 24 liters of homemade vegetable stock. She distributes the stock

Mathematics

2 answers:

ANTONII [103]3 years ago

6 0

Answer:

3 liters

Step-by-step explanation:

pretty simple first grade question, 24/8

OLEGan [10]3 years ago

5 0

24 divided by 8 is 3 because 8x4 is 32 so subtract 32-8 which gives you 24.

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5 tenths + 8 hundreths

gayaneshka [121]

Answer:

50,800

Step-by-step explanation:

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3 years ago

An observer for a radar station is located at the origin of a coordinate system. For the point given, find the bearing of an air

Vinvika [58]

Answer:

as the point (8,0) lies on the x-axis (east) and the bearings are defined with respect to south or north according to the rotation as well. so here the angle is 90 and the directions are N90E or S90W

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3 years ago

1.) Multiply. (x – 7)(2x – 7)

drek231 [11]

hope it will help u......

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3 years ago

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A system contains n atoms, each of which can only have zero or one quanta of energy. How many ways can you arrange r quanta of e

My name is Ann [436]

Answer:

$\mathbf{a)} 2\\ \\ \mathbf{b)} 184 \; 756 \\ \\\mathbf{c)} \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}$

Step-by-step explanation:

If the system contains $n$ atoms, we can arrange $r$ quanta of energy in

$\binom{n}{r} = \dfrac{n!}{r!(n-r)!}$

ways.

$\mathbf{a)}$

In this case,

$n = 2, r=1$ .

Therefore,

$\binom{n}{r} = \binom{2}{1} = \dfrac{2!}{1!(2-1)!} = \frac{2 \cdot 1}{1 \cdot 1} = 2$

which means that we can arrange 1 quanta of energy in 2 ways.

$\mathbf{b)}$

In this case,

$n = 20, r=10$ .

Therefore,

$\binom{n}{r} = \binom{20}{10} = \dfrac{20!}{10!(20-10)!} = \frac{10! \cdot 11 \cdot 12 \cdot \ldots \cdot 20}{10!10!} = \frac{11 \cdot 12 \cdot \ldots \cdot 20}{10 \cdot 9 \cdot \ldots \cdot 1} = 184 \; 756$

which means that we can arrange 10 quanta of energy in 184 756 ways.

$\mathbf{c)}$

In this case,

$n = 2 \times 10^{23}, r = 10^{23}$ .

Therefore, we obtain that the number of ways is

$\binom{n}{r} = \binom{2\times 10^{23}}{10^{23}} = \dfrac{(2\times 10^{23})!}{(10^{23})!(2\times 10^{23} - 10^{23})!} = \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}$

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3 years ago

Which statement is true about the function f(x)= StartRoot negative x EndRoot?

sveticcg [70]

Because x is negative the domain of the function is all negative real numbers.

Set the radical greater than or equal to 0:

-x >= 0

Turn x positive by multiplying both sides by -1. When you multiply an inequality by -1 you need to reverse the inequality sign:

X <= 0

Domain is all real numbers below 0 so all negative real numbers.

6 0

3 years ago

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