There's many properties you can use to find an unknown angle.
There are too many to lists but one core example would be an isosceles triangle that has two adjacent sides and angles.
Let's say that the sides of an isosceles triangle are any number "x"
now since two sides of the triangle are the same we can add these two x's together.
x+x = 2x
now the other side of the triangle can be anything you like. We can call it 4x for this example.
now if we add them all together we'll get 4x+2x=6x
Now since the angles of a triangle add up to 180 degrees
we can equate 6x=180 leaving x to be 30.
Now since x belongs to both sides of the triangle we can say that both angles are congruent as well because the two sides of the triangle are congruent. This is a known triangle law.
Since both angles are now 30 degrees this will leave us with 2(30) = 60
now if we subtract 180 - 60 we'll get 120 which is the remainder of the 3rd angle of the side that corresponds with 4x.
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Hey there, 0.14 kilograms is 140 grams, All I did was 0.14*1000 and that gave me 140
Answer:
The adult and the child ticket are both 8 dollars
Step-by-step explanation:
x =adult ticket price
y = child ticket price
I will assume you forget to put that they sold 2 child tickets on the second day
7x+5y=96 and 3x+2y= 40
I will use elimination. Multiply the first equation by 2 and the second equation by -5 to eliminate y
2(7x+5y)=96*2
14x + 10y = 192
The second equation
-5(3x+2y)= 40*-5
-15x -10y = -200
Add the equations together
14x + 10y = 192
-15x -10y = -200
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-x = -8
Multiply by -1
x = 8
Now we need to find y
3x+2y= 40
3(8) +2y = 40
24+2y = 40
Subtract 24 from each side
24-24 +2y = 40-24
2y = 16
Divide by 2
2y/2 =16/2
y =8
The adult and the child ticket are both 8 dollars
<span>C.
The diagonals are perpendicular.
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