The number of trials and the probability of obtaining success will be given as P(X ≤ 2) = 0.9728.
<h3>How to find that a given condition can be modeled by binomial distribution?</h3>
Binomial distributions consist of n independent Bernoulli trials.
Bernoulli trials are those trials which end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))
Suppose we have random variable X pertaining to a binomial distribution with parameters n and p, then it is written as
X \sim B(n,p)
The probability that out of n trials, there'd be x successes is given by
Assume the random variable X has a binomial distribution with the given probability of obtaining success.
Then the number of trials and the probability of obtaining success will be
P(X ≤ 2), n = 4, p = 0.2
Then we get
Then the cumulative probability will be
Learn more about binomial distribution here:
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The equations are
1. y = 1/2x
2. y = -x - 3
3. y = 1/2x - 3.5
4. y = -5/4x - 1
hope this helps
Answer:
4.5cm, 7.5 cm, 6 cm
Step-by-step explanation:
Multiply 10, 8 and 6 by 0.75 to get answers
122 employees
Because
1/2 of 64 is 32
2/3 of 81 is 54
3/4 of 48 is 36
32+54+36=122