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Mila [183]
2 years ago
8

(d) (1 + cos a) (1 - cos a) /(1 + sin a) (1 - sin a)= tan2 a​

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
5 0

\frac{(1 -  \cos(a))(1 +  \cos(a))  }{(1 -  \sin(a) )(1 +  \sin(a)) }  =  \\

\frac{1 -  {cos}^{2}(a) }{1 -  {sin}^{2}(a) }  =  \\

\frac{ {sin}^{2}(a) }{ {cos}^{2}(a) }  =  \\

{tan}^{2} (a)

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In the circle above, the length of AO is 1, and x = 88º. What is the area of sector AOB?
max2010maxim [7]
The complete question in the attached figure

we know that
[area of a circle]=pi*r²
for r=1 unit
[area of a circle]=pi*1²---------> pi units²

if the area a full circle of 360°--------------> is pi
the area of sector 88°------------------------> X
X=88*pi/360--------> 0.77 units²

the answer is
<span> the area of sector AOB is 0.77 units</span>²

3 0
3 years ago
Read 2 more answers
2(h-8)-h=h-16 what is the solution
BartSMP [9]
STEP-BY-STEP SOLUTION:

To solve this equation, first make ( h ) the subject and then simplify as much as possible as displayed below:

2 ( h - 8 ) - h = h - 16

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4 0
3 years ago
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ANEK [815]

Answer:

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Step-by-step explanation:

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m = (y2-y1)/(x2-x1)

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Match each step of the proof with the justification for the step.
12345 [234]

Answer:

uh

Step-by-step explanation:

4 0
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Answer:

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