Answer:
in family a you multiply by 7
In family b you multiply by 3
Step-by-step explanation:
Sorry if im wrong I should be right if im not then im really sorry :):(
Answer:
250 students
Step-by-step explanation:
Another way of saying this is:
40% of all six-grade students are 100 of them.
So,
40% of total is equal to 100
We can translate this into an algebraic equation and solve for the total number of students.
Let total number of students be "t"
Also, note "of" means "multiplication" and "is" means "equal"
Lets translate word equation to algebraic:
<em>"40% of total is equal to 100"</em>
40% * t = 100
Converting percentage to decimal by dividing by 100, we have:
40% = 40/100 = 0.4
Now, we have:
0.4 * t = 100
We can now solve for t:
Hence,
the total number of students is 250
30000 due at the end of 60 years
I'll assume that the number of days in year is 360
I=30,000×0.05×(60÷360)=250
Cash in hand at the beginning of 60 days is
30,000−250=29,750
The effective rate is
R=I÷pt
R=250÷(29,750×(60÷360))
R=0.0504×100
R=5.04%
Answer:
669cm2
correct question
Charles drew a regular hexagon and divided it into two identical trapezoid , the side length of the hexagon iscoming16cm,the diagonal shown in fig 30 is 32 cm Charles measure the height of one the trapezoid and found that the height was 13.9 cm find the area of the area
Step-by-step explanation:
The side length of the hexagon should be given which is 16 cm
To get the Length the side length makes with the height of the trapezium, Pythagoras theorem is applied to get the base of the triangle
Base = √((16)^2 - (13.9)^2
Base = √62.29
Base = 7.92cm
Since we have gotten the base
Diagonal - the base gives the top length of the trapezium.
32- 7.92- 7.92 = 16.16
The area of the hexagon gives the 2 times of the trapezium.
To find the area of the trapezium
= 1/2 * ( a+b)h
= 1/2* ( 32+ 16.16)* 13.9
= 24.04*13.9
Area of the trapezium = 334.71cm2
= 334.71 * 2
= 669.42cm2
Hope this helps
Answer:
when we multiply 2 and 2 we get answer 4.
