The cross of the position vectors is
.. [5, 2, 2] × [6, -1, 1] = [4, 7, -17] . . . . . the normal vector of the desired plane
Since the origin is a point in the plane, its equation can be written as
.. 4x +7y -17z = 0
The answer was
-35 a^4 -12 a^2 + 12
Hope that helps you
<span>5 1/4 + x + 6 5/6 + 4 2/3 = 22 1/6
5 3/12 + x + 6 10/12 + 4 8/12 = 22 2/12
15 21/12 + x = 22 2/13
</span>16 9/12<span> + x = 22 2/12
x = 22 2/12 - </span>16 9/12<span>
x = </span>21 14/12 - 16 9/12
x = 5 5/12
answer is <span>A. 5 5/12</span>
The answer should be 1/3=12-n
Answer:
75°
Step-by-step explanation:
firstly, use the pythagoras theorem
Square root(8²-2²) = 7.75
Then, use sine
sine A= 7.75/8
Sine A=0.9688
A= (sine power of -1) x (0.9688)
A=75.63
