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2 years ago

Bagles come in bags of eight. how many bagles are in 2 3/4 bags?

Mathematics

1 answer:

vichka [17]2 years ago

6 0

The answer is 22 because you multiple 8 by 2 3/4

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Please help me <br> I have to solve the triangle with the law of sines

Nikitich [7]

Check the picture below.

and since a triangle has a sum of 180° for all interior angles.

A = 180 - 39.34 - 25

A = 115.66

$\bf \cfrac{sin(25^o)}{44}=\cfrac{sin(A)}{a}\implies \cfrac{sin(25^o)}{44}=\cfrac{sin(115.66^o)}{a} \\\\\\ a\cdot sin(25^o)=44\cdot sin(115.66^o)\implies a=\cfrac{44\cdot sin(115.66^o)}{sin(25^o)} \\\\\\ a\approx 93.8452\implies \stackrel{\textit{rounded up}}{a = 93.85}$

make sure your calculator is in Degree mode.

7 0

3 years ago

Read 2 more answers

If a salesperson sells 3/4 of an acre for $80,000, what was the price per square foot rounded to two decimal spaces?

Julli [10]

Now, recalling that for 1 yard, there are 3 feet, therefore $\bf \begin{array}{ll}
yards&feet\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1yd&3ft\\
(1yd)^2&(3ft)^2\\
yd^2&3^2ft^2\\
&9ft^2
\end{array}$

and keeping in mind that, there are 4840 yd² in 1 acre, then

$\bf \cfrac{\quad \frac{3}{4}~\underline{acre}\quad }{80000~\$}\cdot \cfrac{4840~\underline{yd^2}}{\underline{acre}}\cdot \cfrac{9~ft^2}{\underline{yd^2}}\implies \cfrac{\frac{3}{4}\cdot4840\cdot 9~ft^2}{80000~\$}\implies \cfrac{\frac{130680}{4}}{80000}
\\\\\\
\cfrac{\frac{130680}{4}}{\frac{80000}{1}}\implies \cfrac{130680}{4}\cdot \cfrac{1}{80000}\implies \cfrac{3267}{8000}~\frac{ft^2}{\$}~\approx~ 0.408375 ~\frac{ft^2}{\$}$

5 0

3 years ago

PLEASE HELP ME GIVING BRAINLIEST

Scorpion4ik [409]

Answer:

Step-by-step explanation:

Because it starts from the smallest negative prefix to largest

8 0

2 years ago

Seven-eighths equals 0.875 and is a(n) ___.

kirza4 [7]

Answer:

negative number

Step-by-step explanation:

Numerator is 125 as dividing makes 875/1000

Numerator is 0.875 we can divide again by 8.75/10

we find that 0.875 = 875/1000 is equivalent to 7/8

7 0

3 years ago

At a sport clubhouse the coach wants to rope off a rectangular area that is adjacent to the building. He uses the length of the

Furkat [3]

Answer:

w < 8 meters ( w must be greater than 0 because length cannot be 0)

Step-by-step explanation:

One side with building is 23 meters, the other opposite side also will be 23 meters (with rope).

Let width (remaining 2 sides) be "w", he has AT MOST 39 meters of rope, so we can write:

Rope Needed = 23 + 2w < 39

Simplifying:

$23 + 2w < 39\\2w < 39 - 23\\2w < 16\\w < 8$

The range of possible values of w is $w$ meters (of course w has to be greater than 0)

5 0

3 years ago