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3 years ago

How do you write 2.82 in words

Mathematics

2 answers:

Nana76 [90]3 years ago

5 0

Two point eighty two I believe but there are more than just one way to say this in words

SashulF [63]3 years ago

5 0

Two and eighty-two hundredths.

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Two rectangular picture frames have the same area of 45 square inches but have different side lengths. Frame A has a length of 6

AnnyKZ [126]

Ima say B B B B B
That is what I think.

5 0

2 years ago

A recipe for beef stew calls for 1 pound of beef and 3 potatoes the recipe is doubled to include 2 pounds of beef and 6 potatoes

Lerok [7]

Pounds of beef and potatoes are in ratio or proportion of $\frac{1}{3}$ .

<u>Step-by-step explanation:</u>

Correct Question: A recipe for beef stew calls for 1 pound of beef and 3 potatoes. The recipe is doubled to include 2 pounds of beef and 6 potatoes. Which proportion represents the situation?

We have , A recipe for beef stew calls for 1 pound of beef and 3 potatoes , i.e.

Number of beef stew calls = 1

Number of potatoes = 3

Now , The recipe is doubled to include 2 pounds of beef and 6 potatoes i.e. for every 2 pounds of beef we have 6 potatoes

⇒ $2/6$

⇒ $\frac{2}{6}$

⇒ $\frac{2}{2(3)}$

⇒ $\frac{1}{3}$

Therefore , Pounds of beef and potatoes are in ratio or proportion of $\frac{1}{3}$ .

4 0

2 years ago

Read 2 more answers

Wright 6.789 in word form

max2010maxim [7]

Six point seven hundred eighty-nine thousandths.

3 0

2 years ago

Read 2 more answers

The water diet requires you to drink two cups of water every half hour from the time you get up until you go to bed, but otherwi

Elan Coil [88]

Answer:

$7-3.182 \frac{13.638}{\sqrt{4}}= -14.698$

$7+3.182 \frac{13.638}{\sqrt{4}}= 28.698$

Step-by-step explanation:

For this case we have the following info given:

Weight before diet 180 125 240 150

Weight after diet 170 130 215 152

We define the random variable $D = before-after$ and we can calculate the inidividual values:

D: 10, -5, 25, -2

And we can calculate the mean with this formula:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

And the deviation with:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}$

And after replace we got:

$\bar D= 7, s_d = 13.638$

And the confidence interval for this case would be given by:

$\bar D \pm t_{\alpha/2} \frac{s_d}{\sqrt{n}}$

The degrees of freedom are given by:

$df = n-1= 4-1=3$

For the 95% of confidence the value for the significance is $\alpha=0.05$ and the critical value would be $t_{\alpha/2}= 3.182$ . And replacing we got:

$7-3.182 \frac{13.638}{\sqrt{4}}= -14.698$

$7+3.182 \frac{13.638}{\sqrt{4}}= 28.698$

6 0

2 years ago

Please help I’ll make you a branliest!!!!!!!

masya89 [10]

Answer:

2 answer is right

Step-by-step explanation:

I think

7 0

2 years ago