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Amiraneli [1.4K]
2 years ago
6

Can someone solve this? please​

Mathematics
1 answer:
Mariulka [41]2 years ago
5 0

Answer:

Mode = l + [(f₁ - f₀)/(2f₁ - f₀ - f₂)]h

Where, l is the lower limit of the modal class

f₁ is the frequency of the modal class

f₀ is the frequency preceding the modal class

f₂ is the frequency succeeding the modal class

h is the class size

From the table,

Maximum frequency = 41

This frequency lies in the class 10000 - 15000

l = 10000

h = 5000

f₁ = 41

f₀ = 26

f₂ = 16

Now, f₁ - f₀ = 41 - 26 = 15

2f₁ - f₀ - f₂ = 2(41) - 26 - 16

= 82 - 42

= 40

[(f₁ - f₀)/(2f₁ - f₀ - f₂)] = 15/40

= 3/8

Now, mode = 10000 + (3/8)(5000)

= 10000 + (15000/8)

= 10000 + 1875

= 11875

<h3>Therefore, the modal income is 11875.</h3>
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