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Airida [17]
2 years ago
10

NO LINKS!!!Find the indicated side for each triangle below:​

Mathematics
2 answers:
pogonyaev2 years ago
8 0

Problem 5

Apply the Law of Sines

s/sin(S) = r/sin(R)

s/sin(78) = 10/sin(48)

s = sin(78)*10/sin(48)

s = 13.162274

<h3>Answer:    13.162274 approximately</h3>

=============================================================

Problem 6

Use the Law of Sines here as well.

x/sin(X) = y/sin(Y)

x/sin(53) = 6/sin(22)

x = sin(53)*6/sin(22)

x = 12.791588

<h3>Answer:    12.791588 approximately</h3>
Eva8 [605]2 years ago
3 0

Answer:

<u>Sine Rule</u>

\sf \dfrac{a}{sinA}=\dfrac{b}{sinB}=\dfrac{c}{sinB}

(where A, B and C are the angles and a, b and c are the sides opposite the angles)

<u>Question 5</u>

\sf \implies \dfrac{s}{sin(78)}=\dfrac{10}{sin(48)}

\sf \implies s=\dfrac{10sin(78)}{sin(48)}

\sf \implies s=13.16227426

s = 13.2 (nearest tenth)

<u>Question 6</u>

<u />\sf \implies \dfrac{x}{sin(53)}=\dfrac{6}{sin(22)}

\sf \implies x=\dfrac{6sin(53)}{sin(22)}

\sf \implies x=12.79158761

x = 12.8 (nearest tenth)

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Scilla [17]
To turn a number to a percent, multiply by 100 = 600%
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3 years ago
Suppose that we wanted to estimate the true average number of customers at a particular restaurant with 95% confidence. The marg
Ganezh [65]

Answer:

Correct option (A).

Increasing our confidence to 97% will <u>increase the margin of error</u>.

Step-by-step explanation:

The confidence interval for population mean is:

\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

The margin of error is:

MOE = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

The margin of error of is directly proportional to the critical value.

MOE\propto z_{\alpha /2}\\

So if the confidence level is increased from 95% to 97% the critical value will increase.

  • The critical value of <em>z</em> for 95% confidence level is 1.96.
  • The critical value of <em>z</em> for 97% confidence level is 2.17.

If the critical values increases the MOE increases.

Thus, on increasing the confidence level to 97% the margin of error will increase.

7 0
3 years ago
determine the value of m and n for mx^3 +20x^2+ nx-36 when divided by (x+1) gives remainder 0 and when divided by (x-2) gives re
soldi70 [24.7K]

Given:

The given polynomial is

mx^3+20x^2+nx-36

When it divided by (x+1) gives remainder 0 and when divided by (x-2) gives remainder of 45.

To find:

The values of m and n.

Solution:

According to the remainder theorem, if a polynomial P(x) is divided by (x-c), then the remainder is P(c).

Let the given polynomial be P(x).

P(x)=mx^3+20x^2+nx-36

When it divided by (x+1) gives remainder 0. So, P(-1)=0.

P(-1)=m(-1)^3+20(-1)^2+n(-1)-36

0=-m+20-n-36

0=-m-n-16

m+n=-16                   ...(i)

When P(x) is divided by (x-2) gives remainder of 45. So, P(2)=0

m(2)^3+20(2)^2+n(2)-36=45

8m+80+2n-36=45

8m+2n+44=45

8m+2n=45-44

8m+2n=1                  ...(ii)

Multiply 2 on both sides of (i).

2m+2n=-32                   ...(iii)

Subtract (iii) from (ii).

6m=33

m=\dfrac{33}{6}

m=5.5

Putting m=5.5 in (i), we get

5.5+n=-16

n=-16-5.5

n=-21.5

Therefore, the values of m and n are 5.5 and -21.5 respectively.

7 0
3 years ago
Please answer this question, they said the answer has to be in fraction form or hole number
Tpy6a [65]

Answer:

1.6

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
3t-2(t-1) 51-4(2 + 1)
Rasek [7]

Answer:

t+48

Step-by-step explanation:

(3t-2t+2+51-8-4)

(t+2+46)

t+48

(i'm not sure because i think there is supposed to be something before 51)

7 0
3 years ago
Read 2 more answers
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