Question

Find m v I need help with these two questions

Answer 1

Answer:

Step-by-step explanation:-

15)

ABCD is quadrilateral

∠MBC+∠ABC=180°

∠ABC = $\tt 180-71=109^o$

The sum of all angles of quadrilateral = 360°

$\tt 10x+6+12x-2+8x-1+109=360^o$

$\tt 31x+112=360$

$\tt 31x+112-112=360-112$ ( Subtract 112 from both sides)

$\tt 31x=248$  (Simplify)

$\tt \cfrac{31x}{31}=\cfrac{248}{31}$ (Divide both sides by 21)

$\tt x=8$

___

16) Find m∠v

The polygon has 6 sides

Sum of angles:- (6-2)=180= 720°

so,

$\tt 90+9x-19+111+5x+8+128+7x+3=720$

$\tt 2x+321=720$

$\tt 21x+321-321=720-321$ ( Subtract 321 from both sides)

$\tt 21x=399$ (Simplify)

$\tt \cfrac{21x}{21}=\cfrac{399}{21}$ ( Divide both sides by 21)

$\tt x=19$

Therefore, m∠v=19

____