Answer:
I don't know either but thanks for asking me
Answer:
76%
Step-by-step explanation:
In order to find the answer to this question you must divide the output of dividing 42 and 32 by 100 to receive the answer.
42/32
42/32=1.3125
100=1.3125*x
100/1.3125=x
76.1904761905=x
x=76.1904761905
Hope this helps.
Answer:
a: z = -1.936
b: 0.0265
d: z < -1.645
Reject H0 if z < -1.645
Step-by-step explanation:
We are given:
H0: µ = 20
HA: µ < 20
n = 60, sample mean: 19.6, σ = 1.6
Since the alternate hypothesis has a < sign in it, it is a left tailed test. The < or > sign in the alternate hypothesis points towards the rejection region.
For a: We need to calculate the test statistic for our situation. This is done with a z-score formula for samples.
For b: we need to use the z-score table to look up the p-value for the score we calculate in part a. The p-value is 0.0265. This means that there is only about a 2.65% chance that the sample values were a result of random chance.
For d: Since the significance level is 0.05, and this is a one tailed test, we have a critical value of z < - 1.645. This means that if the z-score we calculate in part a is less than -1.645, we will reject the null hypothesis
See attached photo for all the calculations!
The slope is rise/run
3 up and 3 to the left: 3/3 = 1
The slope is 1
Assuming graph is 1 units per box and y intercept is (0,y), looking at the graph you can see it’s (0,-1)
The y intercept is (0,-1)
F(x) = x + 2
when x = 1, f(1) = 1 + 2 = 3
Therefore range for x ≠ 1 is y ≠ 3.