$\frac{1}{2}+ \frac{1}{3} \\ 
 \\ \frac{1*3}{2*3}= \frac{3}{6} \\ 
 \\ \frac{1*2}{3*2}= \frac{2}{6} \\ 
 \\ \frac{3}{6}+ \frac{2}{6}= \frac{5}{6} \\ 
 \\ Answer: \frac{5}{6} \\ 
$

7 0

3 years ago

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30.00

GalinKa [24]

Answer:

(13,-23)

Step-by-step explanation:

Comparing the image coordinates to the transformation rule, you see that ...

(x -4, y +15) = (9, -8)

Adding (4, -15) to these coordinates, we get ...

(x -4, y +15) +(4, -15) = (9, -8) +(4, -15)

(x-4+4, y+15-15) = (9+4, -8-15)

(x, y) = (13, -23) . . . . coordinates of D

4 0

3 years ago

Use the unit circle to evaluate these expressions:

sergeinik [125]

Answer:

a) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4$

For this case we know that $sin (\pi/4) = \frac{\sqrt{2}}{2}$

So then $sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}$

b) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$19 \pi/6 - 2\pi = \frac{7\pi}{6}$

For this case we know that $cos (\pi/6) = \frac{\sqrt{3}}{2}$

And we know that $\frac{7\pi}{6}$ is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then $cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}$

c) For this case that any factor of $\pi$ the sin function is equal to 0.

So from definition of tan we have this:

$tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0$

Step-by-step explanation:

a. sin (17pi / 4 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4$

For this case we know that $sin (\pi/4) = \frac{\sqrt{2}}{2}$

So then $sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}$

b. cos (19pi / 6 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$19 \pi/6 - 2\pi = \frac{7\pi}{6}$

For this case we know that $cos (\pi/6) = \frac{\sqrt{3}}{2}$

And we know that $\frac{7\pi}{6}$ is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then $cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}$

c. tan(450pi)

For this case that any factor of $\pi$ the sin function is equal to 0.

So from definition of tan we have this:

$tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0$

4 0

3 years ago

Please explain and please if you don't know answer in the COMMENT section but however if you do know please answer in the box be

s2008m [1.1K]

Answer 4: Angle 4,5 and 1

Answer 5: 3,4 and 5

Answer 6: The value of x is 10 because since angle 3 is 90 degrees angle 1 is 9x 9 times 10 equals 90 degrees which is the same as angle 3 which is 90 degrees, so the answer is 10.

6 0

3 years ago

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