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Alex777 [14]
3 years ago
11

What are the domain and range of the function represented by the set of

Mathematics
2 answers:
omeli [17]3 years ago
6 0

Answer:

B.

Domain: {-6,-3,1,14}

Range: {-4,-2,0,12}

Step-by-step explanation:

Ap3x

WARRIOR [948]3 years ago
4 0

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Domain = { -6 , -3 , 1 , 14 }

Range = { -4 , -2 , 0 , 12 }

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Thus the correct answer is (( B )) .

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

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A jar with 15 marbles, 7 are red what is the probability
zavuch27 [327]

Answer:

46.6667%

Step-by-step explanation:

Divide 7 by 15 because that's how you calculate the chance of receiving marbles

7/15 is equal to 0.466667 approx..

To convert to Percent form, multiply by 100

0.466667 *100=46.6667

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3 years ago
How would 3,050,000 be expressed in scientific notation? 3.5 ×106 3.05 × 105 3.05 × 106 3.5 × 104
allsm [11]
<span>3,050,000 = 3.05 x 10^6

answer </span><span>3.05 ×10^6 (first choice)</span>
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3 years ago
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How many sixths are in 4
pochemuha
If you would like to know how many sixths are in 4, you can calculate this using the following steps:

n ... the number of sixths
n * 1/6 = 4
n = 4 * 6
n = 24

The correct result would be: 24 sixths are in 4.
3 0
3 years ago
A jar contains 12 red marbles numbered 1 to 12 and 6 blue marbles numbered 1 to 6. A marble is drawn at random from the jar. Fin
lora16 [44]

Answer:

(a)P(Red)=\dfrac{2}{3}\\(b)P(Odd) =\dfrac{1}{2}\\(c)P(\text{Red or Odd Numbered})=\dfrac{5}{6}\\(d)P(\text{Blue or Even Numbered})=\dfrac{2}{3}

Step-by-step explanation:

Number of Red Marbles{1,2,3,4,5,6,7,8,9,10,11,12},n(R)=12

Number of Blue Marbles{1,2,3,4,5,6},n(B)=6

Total Number of Marbles, n(S)=6+12=18

(a)Probability that the Marble is Red

P(R)=\dfrac{n(R)}{n(S)} =\dfrac{12}{18} =\dfrac{2}{3}

(b)Probability that the marble is odd-numbered.

Number of Odd-Numbered Balls, n(O)=9

P(Odd)=\dfrac{n(O)}{n(S)} =\dfrac{9}{18} =\dfrac{1}{2}

(c)Probability that the marble is red or odd-numbered.

n(Red)=12

n(Odd Numbered marbles)=9

n(Red and Odd Numbered Marbles)=6

P(\text{Red or Odd Numbered})=P(Red)+P(Odd\:Numbered)-P(\text{Red and Odd Numbered)}\\=\dfrac{12}{18} +\dfrac{9}{18}-\dfrac{6}{18}  =\dfrac{15}{18}\\P(\text{Red or Odd Numbered})=\dfrac{5}{6}(d)Probability that the marble is blue or even-numbered.

n(Blue)=6

n(Even Numbered marbles)=9

n(Blue and Even Numbered Marbles)=3

P(\text{Blue or Even Numbered})=P(Blue)+P(Even\:Numbered)-P(\text{Blue and Even Numbered)}\\=\dfrac{6}{18} +\dfrac{9}{18}-\dfrac{3}{18}  =\dfrac{12}{18}\\P(\text{Blue or Even Numbered})=\dfrac{2}{3}

5 0
3 years ago
What are the measurement lengths that form a right triangle?
r-ruslan [8.4K]

Answer:

A right triangle is 90 degrees so that means that the other two angles have to equal 90 degrees to get a total of  180 degrees.

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