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xz_007 [3.2K]
2 years ago
12

What is the equation of the line that passes through the point (4,-6) and has a slope of -5/2?

Mathematics
2 answers:
guapka [62]2 years ago
7 0

Answer:

y = (-5/2)X + 4

Step-by-step explanation:

we know that the equation of a line is y = mx + b

m = -5/2

so

y = -5/2x + b

to find b:

-6 = -10 + b

b = 4

so

y = (-5/2)X + 4

nadezda [96]2 years ago
7 0

Answer:

Use the point-slope form of a linear equation:

y-y_1=m(x-x_1)

where:

  • m = slope
  • (x_1,y_1) = point on line

Given:

  • m=-\dfrac52
  • (x_1,y_1)=(4,-6)

Substitute given information into the equation:

\implies y-y_1=m(x-x_1)

\implies y-(-6)=-\dfrac52(x-4)

\implies y+6=-\dfrac52x+10

\implies y=-\dfrac52x+4

Therefore, the equation of the line in different formats is:

\textsf{slope-intercept form: }y=-\dfrac52x+4

\textsf{standard form: }5x+2y=8

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