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2 years ago

What is a possible scale factor for the dilation of the quadrilateral ABCD?

Mathematics

1 answer:

slamgirl [31]2 years ago

6 0

Answer:

$\dfrac {1}{2}$

Step-by-step explanation:

According to the diagram

The center is o

Then Distance from O to B'C'=1

Distance from O to BC=1+1=2

$\therefore\sf Ratio\:is\:1:2.$

<h3>More to know:-</h3><h3>Formulas related to surface area and volume:-</h3>

$\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}$

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Match the solid figure to the appropriate formula.

AlekseyPX

1. $L \cdot A=\pi r l$ - Cone

2. $V=\frac{4}{3} \pi r^{3}$ - Sphere

3. $T \cdot A=2 \pi r h+2 \pi r^{2}$ - Cylinder

4. $V=\frac{1}{3} B h$ - Pyramid

5. $L . A=p h$ - Prism

Solution:

1. $L \cdot A=\pi r l$

Lateral surface area of cone = $\pi r l$

where r is the radius of the cone and l is the slant height of the cone.

2. $V=\frac{4}{3} \pi r^{3}$

Volume of sphere = $\frac{4}{3} \pi r^{3}$

where r is the radius of the sphere.

3. $T \cdot A=2 \pi r h+2 \pi r^{2}$

Total surface area of cylinder = $2 \pi r h+2 \pi r^{2}$

where r is the radius of the cylinder and h is the height of the cylinder.

4. $V=\frac{1}{3} B h$

Volume of pyramid = $\frac{1}{3} B h$

where B is the base area of the pyramid and h is the height of the pyramid.

5. $L . A=p h$

Lateral surface area of prism = $p h$

where p is the perimeter of the base and h is the height of the prism.

4 0

2 years ago

Please help and show work!!

Advocard [28]

1/3x + y = -2

-1/3x -1/3x

y = -1/3x-2

4 0

3 years ago

The matrix method is being used to solve the system of equations x + 2y = 4 and 3x - y = 6.

Ira Lisetskai [31]

Answer: b) multiply row 1 by -3 and add the result to row 2

Step-by-step explanation:

8 0

2 years ago

X^4 + x^3 + x^2 + x=0

kifflom [539]

X^4 + x^3 + x^2 + x = 0

x(x^3 + x^2 + x + 1) = 0

x[x^2(x + 1) + 1(x + 1)] = 0

x(x + 1)(x^2 + 1) = 0 ⇔ x = 0 or x + 1 = 0 or x^2 + 1 = 0

x = 0 or x = -1 or x^2 = -1 -false

Answer: x= 0 or x = -1.

4 0

3 years ago

If y° and 150° form a linear pair , then y° ?

yaroslaw [1]

Answer:

30 degrees

Step-by-step explanation:

A linear pair of angles add upto 180

So, y+150=180

y=180-150

=30

5 0

3 years ago

Read 2 more answers