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ahrayia [7]
3 years ago
6

Pls help me. question in picture​

Mathematics
2 answers:
gogolik [260]3 years ago
8 0

Answer:

(m+6)(m+10).

Step-by-step explanation:

To find this answer, we will need to determine factors of 60 that when added, they are equivalent to 16.

We can begin by listing some factors:

30 and 2

4 and 15

12 and 5

6 and 10

...

Then, we can determine which of these factors can be added together to become 16. From this, we can determine that only factors "6 and 10" become 16 when added together.

When we do this, we can see that only <u>answer 1</u>, (m+6)(m+10), is equivalent to the equation given.

Kisachek [45]3 years ago
7 0

Answer:

a.) (m+6)(m+10)

Step-by-step explanation:

Factor m^2+16m+60

Find what two numbers add up to 16, and equal 60 when multiplied:

6 and 10

6+10=16\\6*10=60

Factor:

(m+6)(m+10)

<em>Finito.</em>

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1) The population of a town was7652in 2016. The population grows at a rate of 1.6%annually.(a)Use the exponential growth model t
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Answer:

1. a) population of the town in 2024 = 8697

2.) the earthquake with a magnitude of 8 is a <u>100 times stronger</u> than an earthquake with a magnitude of 6.

Step-by-step explanation:

1) the population of a town was, N_{0}   = 7652 in 2016.

a) Exponential growth model is given by N(t) = N_{0} e^{kt} where t is the time in years after 2016.

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  k = growth rate constant = 1.6% = 0.016

 i) therefore the population of the town in 2024

    = N = N_{0} e^{kt}  = 7652e^{0.016\times8}  = 8697   ( to the nearest whole number)

2.) log (I \times M \times S) = magnitude of earthquake  where I is the Intensity of the earthquake and S is the intensity of a standard earthquake

therefore  I \times M \times S = 10^{magnitude\hspace{0.1cm}of\hspace{0.1cm}earthquake}

therefore \frac{strength\hspace{0.1cm}of\hspace{0.1cm}earthquake\hspace{0.1cm}1 }{strength\hspace{0.1cm}of\hspace{0.1cm}earthquake\hspace{0.1cm}2}  = \frac{10^{8} }{10^{6} }  = 100

 

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Step-by-step explanation:

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