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1 year ago

ASZPPPPLAST ONEEE PLEASEE HELPP

Mathematics

1 answer:

miskamm [114]1 year ago

7 0

Answer:

Top Left

I sincerely hope this is right and that you get g really good mark ;)

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Please help ASAP!!!!

katrin [286]

The answer is B i had this problem.

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2 years ago

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Sin2alpha+cos2alpha-cos6alpha/sin4alpha+2sin²alpha-1<br><br> if alpha is -135°

balandron [24]

Answer:

$= \frac{\sin(2 \alpha ) + \cos(2 \alpha ) - \cos(6 \alpha ) }{ \sin(4 \alpha ) + 2 { \sin }^{2} \alpha - 1} \\ = \frac{ \sin( - 270) + \cos( - 270) - \cos( - 810) }{ \sin( - 540) + 2 { \sin }^{2}( - 135) - 1 } \\ = \frac{1}{ - 2} \\ = - 0.5$

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1 year ago

Mathematics algebra sat

Leya [2.2K]

Hey there!

2(p + 1) + 8(p - 1) = 5p

2(p) + 2(1) + 8(p) + 8(-1) = 5p

2p + 2 + 8p - 8 = 5p

10p - 6 = 5p

SUBTRACT 5p to BOTH SIDES

10p - 6 - 5p = 5p - 5p

SIMPLIFY IT!

5p - 6 = 0

ADD 6 to BOTH SIDES

5p - 6 + 6 = 0 + 6

CANCEL out: -6 + 6 because it gives you 0

KEEP: 0 + 6 because it helps solve for the p-value

5p = 0 + 6

5p = 6

DIVIDE 5 to BOTH SIDES

5p/5 = 6/5

CANCEL out: 5/5 because it gives you 1

KEEP: 6/5 because gives you the result of the p-value

SIMPLIFY IT!

p = 6/5

Therefore, your answer is: p = 6/5

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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2 years ago

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Use the relationship between the angles in the figure to answer

Sholpan [36]

31+40 = 71. 180-71=109

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2 years ago

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In 2012 your car was worth $10,000. In 2014 your car was worth $8,850. Suppose the value of your car decreased at a constant rat

monitta

Answer:

The function to determine the value of your car (in dollars) in terms of the number of years t since 2012 is:

$f(t) = 10000(0.9407)^t$

Step-by-step explanation:

Value of the car:

Constant rate of change, so the value of the car in t years after 2012 is given by:

$f(t) = f(0)(1-r)^t$

In which f(0) is the initial value and r is the decay rate, as a decimal.

In 2012 your car was worth $10,000.

This means that $f(0) = 10000$ , thus:

$f(t) = 10000(1-r)^t$

2014 your car was worth $8,850.

2014 - 2012 = 2, so:

$f(2) = 8850$

We use this to find 1 - r.

$f(t) = 10000(1-r)^t$

$8850 = 10000(1-r)^2$

$(1-r)^2 = \frac{8850}{10000}$

$(1-r)^2 = 0.885$

$\sqrt{(1-r)^2} = \sqrt{0.885}$

$1 - r = 0.9407$

Thus

$f(t) = 10000(1-r)^t$

$f(t) = 10000(0.9407)^t$

7 0

2 years ago