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3 years ago

Someone help please :(

Mathematics

2 answers:

gayaneshka [121]3 years ago

6 0

3 Because if you do 68-65 u will get 3

xeze [42]3 years ago

4 0

Answer:

47 I believe

Step-by-step explanation:

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68% of the tickets sold at a water park were child tickets. If the park sold 50 tickets in all, how many child tickets did it se

Mnenie [13.5K]

Answer:

$\boxed{\bf\: The \: park \: sold \boxed{ 34{}} \: child \: tickets.}$

Step-by-step explanation:

Given:

Percentage of Tickets sold at a water park - 68%

The Number of Tickets if the park sold in all - 50

To Find:

The Number of child tickets the park sold.

Solution:

We know that 68% equals to 68/100.

Step 1: Multiply 68/100 by 50 which is the number of tickets the park sold :-

$\sf \: = \: \cfrac{68}{100} \times 50$

Note:The Simplified form of 68/100 * 50 would be the answer to this question.

Step 2: Cancel One zero of 50 and one zero of 100,That is:-

$\sf = \cfrac{68}{ 10\cancel0} \times 5 \cancel0$

Results to,

$\sf = \cfrac{68}{10} \times 5$

Step 3: Cancel 5 and 10, That is:-

$\sf = \cfrac{68}{ \cancel{10 }} \times \cancel5$

Results to,

$\sf =\: \cfrac{68}{2} \times 1$

$\sf = \cfrac{68}{2}$

Step 4: Cancel 68 and 2, That is:-

$\sf =\: \cfrac{ \cancel{68}}{ \cancel2}$

Results to,

$\sf = \cfrac{34}{1}$

$\sf = 34$

34 is the result.

Hence,

$\underline{ \rm \: The \: park \: sold \: \bold{ 34 } \: child \: tickets.}$

________________________________

I hope this helps!

Let me know if you have any questions.I am joyous to help!

6 0

3 years ago

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maksim [4K]

Answer:

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Step-by-step explanation:

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3 years ago

Which equation represents an inverse variation?

Sphinxa [80]

Answer: Choice C) y = 30/x

Inverse variation equations are of the form y = k/x. In this case, k = 30. We can rearrange the format to get x*y = k after multiplying both sides by x. So y = 30/x can be turned into x*y = 30.

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3 years ago

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Maru [420]

Answer:

17) x=7

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20) x= 6

Step-by-step explanation:

17) is congruent

18) is supplementary

19) is congruent

20) is congruent

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