The vector AB is not related with the vector CD as k is not the same for each pair of components.
<h3>Are two vectors similar?</h3>
In this question we must prove if the vector AB is a multiple of the vector CD, that is:

![\vec B - \vec A = k \cdot [\vec D - \vec C]](https://tex.z-dn.net/?f=%5Cvec%20B%20-%20%5Cvec%20A%20%3D%20k%20%5Ccdot%20%5B%5Cvec%20D%20-%20%5Cvec%20C%5D)
(1, 4) - (2, 3) = k · [(- 2, 2) - (1, 3)]
(- 1, 1) = k · (- 3, - 1)
Hence, the vector AB is not related with the vector CD as k is not the same for each pair of components.
To learn more on vectors: brainly.com/question/13322477
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(2+2i)(5+3i)
10+6i+10i+6i^2
10+16i+6(-1)
4+16i
When you have an “i^2”, you also have a negative one. The simplified answer is 4+16i
Rounded answer is 7.66
Regular answer is 7.65966
Answer:
0.81649658092
Step-by-step explanation:
The square root of 6 equals 2.44948974278. Divide that by 3, and you are given 0.81649658092.