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3 years ago

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At the end of a Pizza party 1/3 of a cheese pizza and 1/6 of a pepperoni pizza or left brand ate 1/2 of all the leftover pizza w

hat fractional part of a whole pizza did Brand eat

1 answer:

Zina [86]3 years ago

4 0

Answer:

1/6

Step-by-step explanation:

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Please explain i will mark brainliesttt!

Sati [7]

Answer:

<em>Answer is </em><em>given below with explanations</em><em>. </em>

Step-by-step explanation:

$given \: the \: line \: n \: passes \: through \\ \: ( - 3, - 7.5) \: \: and(2, - 5) \\ the \: equation \: of \: the \: line \: is \\ \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} \\ here \: x1 = - 3 \: \: \: y1 = - 7.5 \\ and \: \: x2 = 2 \: \: \: y2 = - 5 \\ \frac{y - ( - 7.5)}{ - 5 - ( - 7.5)} = \frac{x - ( - 3)}{2 - ( - 3)} \\ \frac{y + 7.5}{ - 5 + 7.5} = \frac{x + 3}{2 + 3} \\ \frac{y + 7.5}{2.5} = \frac{x + 3}{5} \\ dividing \: by \: 5 \: on \: both \: side s\\ \frac{y + 7.5}{0.5} = \frac{x + 3}{1} \\ 0.5(x + 3) = y + 7.5 \\ 0.5x + 1.5 = y + 7.5 \\ 0.5x - y - 6 = 0 \\ is \: the \: required \: equation.$

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

5 0

3 years ago

Let’s assume that human body temperatures are normally distributed with a mean of 98.20° F and a standard deviation of 0.62° F.

uysha [10]

Answer: It is such a small percentage of the population that would be considered to have fever at that level.

So, it is not appropriate stringent standard.

Step-by-step explanation:

Since we have given that

Mean = 98.20°F

Standard deviation = 0.62°F

If Bellevue Hospital in New York City uses 100.6°F as the lowest temperature considered to be a fever.

So, $\bar{X}=100.6^\circ F$

So, using the normal distribution, we first find the value of z.

$z=\dfrac{\bar{x}-\mu}{\sigma}\\\\x=\dfrac{100.6-98.2}{0.62}\\\\z=3.87$

Since z = 3.87

So, p = 0.0001 =0.1%

So,It is such a small percentage of the population that would be considered to have fever at that level.

So, it is not appropriate stringent standard.

4 0

3 years ago

What is the surface area of each triangular prism?

SOVA2 [1]

the surface area of the above triangular prism is 156 square inches.

Step-by-step explanation:

multiply the sum of the triangle sides by the height of the prism and add the values together for the answer, remembering to include the correct unit of measurement.

8 0

3 years ago

It takes 36 minutes for 7 people to paint 4 walls. How long does it take 9 people to paint 7 walls?

algol [13]

It will take 49 minutes for 9 people to paint 7 walls

7 0

3 years ago

The length around the outside of semicircle O from point L through point M to point N is 14 centimeters. The perimeter of semici

Luden [163]

The area would be 83.67 cm.

A semicircle is half of a circle. The perimeter of the semicircle would be half of the perimeter (circumference) of the entire circle. The formula for circumference is:

C=πd

Using our information, we have

22.92 = 0.5(3.14)d
22.92 = 1.57d

Divide both sides by 1.57:

22.92/1.57 = 1.57d/1.57
14.6≈d

Since the diameter is 14.6, the radius is 14.6/2 = 7.3.

We use the radius for the area of the semicircle:

A=0.5πr²
=0.5(3.14)(7.3)²
=83.67

3 0

3 years ago