Answer:
NO
Step-by-step explanation:
The changeability of a sampling distribution is measured by its variance or its standard deviation. The changeability of a sampling distribution depends on three factors:
- N: The number of observations in the population.
- n: The number of observations in the sample.
- The way that the random sample is chosen.
We know the following about the sampling distribution of the mean. The mean of the sampling distribution (μ_x) is equal to the mean of the population (μ). And the standard error of the sampling distribution (σ_x) is determined by the standard deviation of the population (σ), the population size (N), and the sample size (n). That is
μ_x=p
σ_x== [ σ / sqrt(n) ] * sqrt[ (N - n ) / (N - 1) ]
In the standard error formula, the factor sqrt[ (N - n ) / (N - 1) ] is called the finite population correction. When the population size is very large relative to the sample size, the finite population correction is approximately equal to one; and the standard error formula can be approximated by:
σ_x = σ / sqrt(n).
easy peasy.
-84/14= -6
feel free to add me as a friend I am very good at math and am willing to help.
Answer:
![[km^2]](https://tex.z-dn.net/?f=%5Bkm%5E2%5D)
Step-by-step explanation:
In this problem, the initial area of the forest at time t = 0 is

After every year, the area of the forest decreases by 9.8%: this means that the area of the forest every year is (100%-9.8%=90.2%) of the area of the previous year.
So for instance, after 1 year, the area is

After 2 years,

And so on. So, after t years, the area of the forest will be

And by substituting the value of A0, we can find an explicit expression:
![[km^2]](https://tex.z-dn.net/?f=%5Bkm%5E2%5D)
Answer:
1 5/24 total gallons remain
Step-by-step explanation:
yellow: 4/3 - 3/4 = 16/12-9/12 = 7/12
green: 5/4 - 3/4 = 5/4-3/4 = 2/4
blue: 7/8 - 3/4 = 14/16-12/16 = 2/16
7/12 + 2/4 + 2/16 = 28/48 + 24/48 + 6/48 =
58/48 or 1 5/24