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Zolol [24]
2 years ago
8

Use the grouping method to factor x³ + x² + 3x+3.

Mathematics
1 answer:
Annette [7]2 years ago
8 0

Answer:

D. (x + 1)(x^2 + 3)

Step-by-step explanation:

Hello!

We can group the first two terms and the last two terms.

<h3>Factor by Grouping</h3>
  • x^2 + x^2 + 3x + 3
  • x^2(x + 1) + 3(x + 1)
  • (x^2 + 3)(x + 1)

Factoring by grouping is the process of breaking down larger polynomials to smaller ones to factor. We can then combine like factors.

In the second step, we can see that we can rewrite x^3 + x^2 as x^2(x + 1), as both the two terms share a common factor of x^2. We can pull out x^2 from that expression. Similarly, 3x and 3 share a common factor of 3, so we can pull that out.

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The answer is: the square (2.5x2.5).
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3 years ago
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Answer:

its type hard to see ngl

Step-by-step explanation:

8 0
3 years ago
What is the slope of this line?<br> -1/5<br> 1/5<br> 5<br> -5
Tems11 [23]

Answer:

1/5

Step-by-step explanation:

The slope of a line at any given point is Rise/run

If I start at Point (0,2) and go to point (5,3)

I have to Rise 1 point up.

I go across, or run, 5.

1/5

8 0
2 years ago
Two pipes can fill a tank in 19 minutes if both are turned on. If only one is used, it would take 49 minutes longer for the smal
a_sh-v [17]

Answer:

The time taken by smaller pipe to fill the tank alone is 74.2 min

Step-by-step explanation:

Given as :

The time taken by two pipes to fill tank = 19 min

Let the time taken by larger pipe to fill tank = y

And the time taken by smaller pipe to fill tank = x

According to question

The smaller pipe takes 49 minutes longer than larger pipe

I.e x = y + 49

Now,

\dfrac{1}{x} + \dfrac{1}{y} = \dfrac{1}{49}

Or, \dfrac{1}{y + 49} + \dfrac{1}{y} = \dfrac{1}{49}

Or, \dfrac{y + 49 + y}{y^{2} + 49 y } = \dfrac{1}{49}

Or, 2 y + 49 = \dfrac{y^{2}+49y }{19}

Or, 19 × ( 2 y + 49 ) = y² + 49 y

Or, 38 y + 931 = y² + 49 y

Or, y² + 49 y - 38 y - 931 = 0

or, y² + 11 y - 931 = 0

Or, Applying quadratic equation method to calculate the value of y

so, y = \frac{- b \pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

Or,  y = \frac{- 11 \pm \sqrt{11^{2}-4\times 1\times (-931)}}{2\times 1}

Or, y = \frac{- 1 \pm \sqrt{121+3724}}{2}

or, y = \frac{- 1 \pm \sqrt{3845}}{2}

or, y = \frac{- 1 \pm 62.008}{2}

∴   y = 25.2 , - 36.5

So, The time taken by larger pipe = y = 25.2 min

and the time taken by smaller pipe to fill the tank = y + 49 = 25.2 + 49 = 74.2 min

Hence The time taken by smaller pipe to fill the tank alone is 74.2 min answer

6 0
2 years ago
What is 20 add blank equals 63?
MArishka [77]
To figure this out, you do 63 - 20 which is 43. I hope this helps!
8 0
3 years ago
Read 2 more answers
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