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3 years ago

5

The freight is traveling at a constant speed the table below shows how far the train travels after different amounts of time com

plete the table below.
Write an equation for “d” , the distance traveled by the train after “h” hours

1 answer:

Artist 52 [7]3 years ago

5 0

Using the 2nd row it traveled 120 miles in 3 hours
so 120/3 = 40 miles per hour

so distance (d) = 40h

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Sheila had one gallon of milk. She used gallon of milk to make ice cream. She used another gallon of milk to make cookie dough.

never [62]

Answer:

Step-by-step explanation:

we know that

1) Sheila had 1 gallon of milk

2) she used 1/4 of a gallon of milk ------> 1-1/4-----> 3/4 gallon left

3) she used 1/6 of a gallon of milk------> 3/4-1/6---> (6*3-4*1)/24---> 14/24

14/24-----> 7/12 gallon

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3 years ago

The floor of a storage unit is 5 feet

Oliga [24]

I don’t know but I hope you had a good day

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2 years ago

If the measure of angle 1 is (3 x minus 4) degrees and the measure of angle 2 is (4 x + 10) degrees, what is the measure of angl

arlik [135]

Answer:

58 degrees

Step-by-step explanation:

If angle 1 + angle 2 = 90 degrees, then:

(3x - 4) + (4x+10) = 90

Combine like terms:

(3x+4x) + (10-4) = 90

7x + 6 = 90

Subtract 6 from both sides:

7x = 84

Divide both sides by 7:

x = 12

**Plug x back into angle 2 (This step is easy to forget!):

angle 2 = 4(12) + 10

angle 2 = 48 + 10

angle 2 = 58 degrees

4 0

3 years ago

You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

7 0

1 year ago

Josh walks 18 dogs each week. Today, he is walking 1/3 of the dogs. How many dogs is he walking today?

Amiraneli [1.4K]

18*(1/3) (or one third of eighteen) = 6 dogs

4 0

3 years ago