Advice:
I've seen this around quite a bit. what image is it referring to? I cannot answer this because there is no image.
In order to solve this problem, you need to use a geometric series:
where:
a₁ = first term of the series = 36000
r = common rate = 10% raise, therefore 1.10
n = number of terms = 5
Therefore,
<span>
= 219783.60 $
Luke's total earnings in five years are
<span>
219783.60 $.</span>
</span>
9514 1404 393
Answer:
1.63 cm (across the centerline from release)
Step-by-step explanation:
If we assume time starts counting when we release the weight from its fully-extended downward position, then the position at 1.15 seconds can be found from ...
h(t) = -7cos(2πt/4)
h(1.15) = -7cos(π·1.15/2) = -7(-0.233445) ≈ 1.63412 . . . cm
That is, 1.15 seconds after the weight is released from below the resting position, it will be 1.63 cm above the resting position.
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If it is released from <em>above</em> the resting position, it will be 1.63 cm <em>below</em> the resting position at t=1.15 seconds.
B. Step 1. 14x - 6 = 9
Step 2. 14x = 15
Answer:
Eh cafe donete mal reo jama kolotake? 24 eh moi -09....? kelare mei osaje.
Step-by-step explanation: