Question

A cow gave 8 1 2 liters of milk in the morning, 3 5 liters less than this at the noon milking, and 6 3 10 liters in the evening. How many liters of milk did the cow give during the entire day?

Answer 1

Answer:

$22\frac{7}{10}\ l$  or $22.7\ l$

Step-by-step explanation:

The correct question is

A cow gave 8 1\2 liters of milk in the morning, 3\5 liters less than this at the noon milking, and 6 3/10 liters in the evening. How many liters of milk did the cow give during the entire day?

we know that

The total liters of milk given by the cow during the entire day is equal to the amount in the morning plus the amount at the noon plus the amount in the evening.

Let

x -----> liters of milk given by the cow in the morning

y ----> liters of milk given by the cow at the noon

z -----> liters of milk given by the cow in the evening

T ----> total liters of milk given by the cow during the entire day

T=x+y+z

we have

$x=8\frac{1}{2}\ l=\frac{8*2+1}{2}=\frac{17}{2}=\frac{85}{10}\ l$

$y=\frac{17}{2}-\frac{3}{5}=\frac{85-6}{10}=\frac{79}{10}\ l$

$z=6\frac{3}{10}\ l=\frac{6*10+3}{10}=\frac{63}{10}\ l$

$T=\frac{85}{10}+\frac{79}{10}+\frac{63}{10}$

$T=\frac{227}{10}\ l$

$T=22.7\ l$

Convert to mixed number

$22.7\ l=22+0.7=22+\frac{7}{10}=22\frac{7}{10}\ l$