In a direct variation relationship the values must satisfy that y = kx. This si y is always a constant value (k) times x.
So, you can find multiple values that meet this:
y = kx => k = y / x = 11 / 18
=> y = (11/18)x
Now you can give any value to x and fint the value of x that satisfy the relationship:
x y = (11/18)x
1 11/18
2 11/18 * 2 = 11/9
18 11/18 * 18 = 11
36 11/18 * 36 = 22
So, there you have several additional values for x and y in the same relationship that y = 11 and x = 18, and you can find many more using the same rule: y = (11/18)*x
The polynomial function of the least degree with integral coefficient that has the given zeros is <span>y = (x+2)(x-2)(x-4)(x-6). I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications about the said problem.</span>
Answer:
x=-34
Step-by-step explanation:
x-44=-78
Add 44 to each side
x-44+44 = -78+44
x = -34
Answer is C.9(3r-4) and 27r-36
Step-by-step explanation: