Answer:
HEy, dont every do tht
Step-by-step explanation:
The inequalities which matches the graph are: x ≥ ₋1.5 and ₋1.5 ≤ x
Given, a number line is moving from ₋3 to ₊5 .
Next a mark is made at ₋1.5 and everything to its left is shaded which means not visible.
When we mark the point and shade the left part of it then we can start applying the inequality expressions.
And from that we can match the applicable inequalities while observing the graph.
- For the first inequality ₋1.5 ≥ x.Here,x value ranges from ₋1.5 to ₊5, hence we take this as an inequality expression.
- Next, if we consider x ≤ ₋1.5, then here x value will range from ₋1.5 to ₋3. where the region is shaded. Hence this expression doesn't satisfy the graph.
- the next expression is ₋1.5 ≤ x. here the value will again range in the shaded area so it is not applicable.
- ₋1.5 ≥ x, here the values will satisfy the graph.
- remaining inequality expressions does not support the graph.
Therefore the only inequalities the graph represents is x ≥ ₋1.5 and ₋1.5 ≤ x
Learn more about "Linear Inequalities" here-
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Answer:
all you do is multiply 3.6 and 109 to see if its 45,000 per year
Step-by-step explanation:
Answer:
The answer is below
Step-by-step explanation:
The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds: A linear model with ordered pairs at 0, 60 and 2, 75 and 4, 75 and 6, 40 and 8, 20 and 10, 0 and 12, 0 and 14, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet. Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(s) of the domain is the water balloon's height staying the same? (2 points) Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points) Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds.
Answer:
Part A:
Between 0 and 2 seconds, the height of the balloon increases from 60 feet to 75 feet at a rate of 7.5 ft/s
Part B:
Between 2 and 4 seconds, the height stays constant at 75 feet.
Part C:
Between 4 and 6 seconds, the height of the balloon decreases from 75 feet to 40 feet at a rate of -17.5 ft/s
Between 6 and 8 seconds, the height of the balloon decreases from 40 feet to 20 feet at a rate of -10 ft/s
Between 8 and 10 seconds, the height of the balloon decreases from 20 feet to 0 feet at a rate of -10 ft/s
Hence it fastest decreasing rate is -17.5 ft/s which is between 4 to 6 seconds.
Part D:
From 10 seconds, the balloon is at the ground (0 feet), it continues to remain at 0 feet even at 16 seconds.
Answer:
QUESTION ONE-
Cross multiply:
5 * 15 = 12 * y
Simplifying
5 * 15 = 12 * y
Multiply 5 * 15
75 = 12 * y
Solving
75 = 12y
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '-12y' to each side of the equation.
75 + -12y = 12y + -12y
Combine like terms: 12y + -12y = 0
75 + -12y = 0
Add '-75' to each side of the equation.
75 + -75 + -12y = 0 + -75
Combine like terms: 75 + -75 = 0
0 + -12y = 0 + -75
-12y = 0 + -75
Combine like terms: 0 + -75 = -75
-12y = -75
Divide each side by '-12'.
y = 6.25
Simplifying
y = 6.25
QUESTION TWO-
Cross multiply:
8 * w = 20 * 6
Simplifying
8 * w = 20 * 6
Multiply 20 * 6
8w = 120
Solving
8w = 120
Solving for variable 'w'.
Move all terms containing w to the left, all other terms to the right.
Divide each side by '8'.
w = 15
Simplifying
w = 15
QUESTION 3-
Cross multiply:
s + 1 * 8 = 4 * 4
Simplifying
s + 1 * 8 = 4 * 4
Reorder the terms:
1 + s * 8 = 4 * 4
Reorder the terms for easier multiplication:
8 * 1 + s = 4 * 4
1 * 8 + s * 8 = 4 * 4
8 + 8s = 4 * 4
Multiply 4 * 4
8 + 8s = 16
Solving
8 + 8s = 16
Solving for variable 's'.
Move all terms containing s to the left, all other terms to the right.
Add '-8' to each side of the equation.
8 + -8 + 8s = 16 + -8
Combine like terms: 8 + -8 = 0
0 + 8s = 16 + -8
8s = 16 + -8
Combine like terms: 16 + -8 = 8
8s = 8
Divide each side by '8'.
s = 1
Simplifying
s = 1
Step-by-step explanation:
