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Semmy [17]
3 years ago
12

HELP WILL MARK YOU BRAINLIEST NO FAKE ANSWERS

Mathematics
1 answer:
Elis [28]3 years ago
7 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The given statement can be represented as :

  • 2b³ - b

where, the number is assumed to be " b "

therefore, the correct choice is B. 2b³ - b

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In ASTU, the measure of ZU=90°, the measure of ZS=25°, and US = 15 feet. Find the
kramer

Answer:

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7 0
3 years ago
Find the midpoint of the segment joining the points (7,-4) and (9,4).
umka21 [38]
Jus take the average
so
the midpoint of
(x1,y1) and (x2,y2) is
((x1+x2)/2,(y1+y2)/2)
basically average the x and y terms


so
(7,-4) and (9,4)
average of 7 and 9 is 8
average of -4 and 4 is 0
(8,0) is the midpoint

A
5 0
3 years ago
"Leo and Stan start to ride their bikes at the same time from the same point on a
Ymorist [56]

Answer:

6 minutes

Step-by-step explanation:

Given

Leo = 36 sec / rev

Stan = 40 sec/rev

Required

Determine the time (in minutes) they'll meet again

We start by getting the multiples of 36 and 40 uptil we get a common multiple.

Leo: 36 = 36, 72, 108, 144, 180, 216, 252, 288, 324, 360, .....

Stan: 40 = 40, 80, 120, 160, 200, 240, 280, 320, 360....

From above, the common multiple is:

Common Multiple = 360

This means that they'll meet at 360 seconds

Convert to minutes

360 sec = 360/60 mins

360 Seca = 6 mins

Hence,it will take them 6 minutes to meet again at the starting point

3 0
3 years ago
Which point would map onto itself after a reflection across the line y = –x?
Rudiy27

Answer:

+x=-y

Step-by-step explanation:

5 0
3 years ago
Which expression is equivalent to
Nat2105 [25]

Answer : The correct option is \frac{1}{36a^{4}b^{10}}

Step-by-step explanation :

According to the BODMAS rule, when the expression contains brackets open ((), {}, []) we have to first simplify the bracket followed by of (powers and roots etc.) and then we have to solve the division, multiplication, addition and subtraction from left to right order (respectively).

The given expression is:

[\frac{(2a^{-3}b^4)^2}{(3a^5b)^{-2}}]^{-1}

=[\frac{(3a^5b)^{-2}}{(2a^{-3}b^4)^2}]^{1}

=[\frac{1}{(3a^5b)^{2}}\times \frac{1}{(2a^{-3}b^4)^2}]

=[\frac{1}{9a^{10}b^2}\times \frac{1}{4a^{-6}b^8}]

=[\frac{1}{9a^{10}b^2}\times \frac{a^6}{4b^8}]

=\frac{1}{36a^{4}b^{10}}

Thus, the given expression is equivalent to \frac{1}{36a^{4}b^{10}}

5 0
4 years ago
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