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Semmy [17]
2 years ago
12

HELP WILL MARK YOU BRAINLIEST NO FAKE ANSWERS

Mathematics
1 answer:
Elis [28]2 years ago
7 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The given statement can be represented as :

  • 2b³ - b

where, the number is assumed to be " b "

therefore, the correct choice is B. 2b³ - b

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cesar left the college traveling 12 mph. Then, 4 hours later, Gabriel left traveling the same direction at 24 mph. How long will
Sloan [31]

Answer:

Step-by-step explanation:

Given that cesar left the college traveling 12 mph. Then, 4 hours later, Gabriel left traveling the same direction at 24 mph.

Before Gabriel started Cesar would have travelled for 4 hours

So distance travelled by Cesar in 4 hours =4(12) =48 miles

Thus Cesar is ahead of Gabriel by 48 miles

Difference of speed =(24-12) =12 mph

So to catch Cesar time required = 48/difference in speed

= 4 hours

It will take 4 hours.

8 0
3 years ago
A clock that loses 5 seconds each hour has not been reset for 48 hours. What time does the clock show if the correct time is 8:4
nikklg [1K]

Answer:

8:45

Step-by-step explanation:

5x48=240 sec

240 sec = 4 min

8:49-4min= 8:45

7 0
2 years ago
Read 2 more answers
What is net worth why do people say he or she is worth that?
Deffense [45]

Answer:

The net worth of a person is the difference between a person's assets (non-financial and financial) that he/she owns and the debt that person owes.

Value of Assets - Debt and liabilities = Net Worth

5 0
3 years ago
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
The line segment AB is shown below. Which transformation of AB will produce a line segment A’B’ that is parallel to AB
Soloha48 [4]

Answer:

Are there answer choices or do you have to type it in yourself?

4 0
3 years ago
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