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OverLord2011 [107]
3 years ago
10

What is the area of the figure?

Mathematics
1 answer:
masya89 [10]3 years ago
3 0

Step-by-step explanation:

∆=3*6=18

[]=5*15=75

75+18=93 in squared

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kodGreya [7K]

Answer:

The ratio is 2:3.  10m:15m is the fraction 10/15.  Reduce to 2/3.  The ratio is 2:3.

Step-by-step explanation:

4 0
2 years ago
A rectangular room has a perimeter of 70m and is 20m long write an equation to represent the area
ladessa [460]
70-40= 30
30/2 = 15
40/2= 20
15 x 20 = 300
5 0
3 years ago
Which is the answer
coldgirl [10]

Answer:b

Step-by-step explanation:

6 0
2 years ago
Use substitution process to find x,y,and z from the equations 2x+4y+3z=14 , y+3z=11 , z=4
katen-ka-za [31]

Work backwards.

Start with z = 4.

Now deal with the middle equation

y + 3z = 11                    Substitute z = 4 and solve for y

y + 3(4) = 11                  Subtract 12 from both sides

y + 12 = 11

y + 12 - 12 = 11 -12         Combine terms on the left and right

y = - 1                             Now use the top equation for x

z = 4                              z still = 4

2x + 4(-1) +3(4) = 14

2x - 4 + 12 = 14              Solve 3z

2x + 8 = 14                     Subtract 8

2x + 8 - 8 = 14 - 8          Combine

2x = 6                            Divide by 2

x = 6/2

x = 3

Answer

x = 3

y = - 1

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6 0
2 years ago
"A sample of 30 randomly selected oranges was taken from a large population, and their diameters were measured. The mean diamete
Yuki888 [10]

Answer:

The lower bound of the interval is 88.9mm and the upper bound is 93.1mm.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.85}{2} = 0.075

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.075 = 0.925, so z = 1.44

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.44*\frac{8}{\sqrt{30}} = 2.1

The lower end of the interval is the sample mean subtracted by M. So it is 91 - 2.1 = 88.9mm.

The upper end of the interval is the sample mean added to M. So it is 91 + 2.1 = 93.1 mm

The lower bound of the interval is 88.9mm and the upper bound is 93.1mm.

6 0
3 years ago
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