Convert 170 kg/m^3 to g/cm^3.

1 answer:

6 0

Keeping in mind that there are 1000 grams in a KILOgram and that in 1 meter there are 100 cm, therefore in 1 m³, there are (100 cm)³, or 100³ cm³, then

$\bf \cfrac{170~\underline{kg}}{\underline{m^3}}\cdot \cfrac{1000~g}{\underline{kg}}\cdot \cfrac{\underline{m^3}}{100^3~cm^3}\implies \cfrac{170\cdot 1000~g}{100^3~cm^3}\implies \cfrac{170\cdot 1000~g}{1000000~cm^3}
\\\\\\
\cfrac{170\cdot 1~g}{1000~cm^3}\implies \cfrac{170~g}{1000~cm^3}\implies \cfrac{17~g}{100~cm^3}\implies 0.17\frac{g}{cm^3}$

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Answer:

The calculated value Z = 2.3084 > 1.96 at 5% level of significance

Null hypothesis is rejected

Alternative hypothesis is accepted

The hotel does not expects that 24% of all guests will request smoking rooms

Step-by-step explanation:

Step(i):-

Given the hotel takes a random sample of 223 guests. Out of this sample, 39 guests requested smoking rooms.

Sample proportion

p = x/n = 39/223 = 0.174

Given Population proportion 'P' = 0.24

Given random sample size 'n' = 223

Level of significance ∝ =0.05

The critical value Z₀.₀₅ = 1.96

Null Hypothesis (H₀) : P=0.24

Alternative Hypothesis (H₁) : P≠ 0.24

Step(ii):-

Test statistic

$Z = \frac{p-P}{\sqrt{\frac{PQ}{n} } }$

$Z = \frac{0.174-0.24}{\sqrt{\frac{0.24 X 0.76}{223} } }$

|Z| = | -2.3084|= 2.3084

The calculated value Z = 2.3084 > 1.96 at 5% level of significance

Null hypothesis is rejected

Alternative hypothesis is accepted

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