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1 year ago

I am a polygon that has two pairs of opposite sides that are parallel what am I

Mathematics

2 answers:

docker41 [41]1 year ago

8 0

A Parallelogram because it is a quadrilateral with 2 pairs of parallel sides!

melisa1 [442]1 year ago

3 0

Answer: Parallelogram

Step-by-step explanation:

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X−8π=π someone help me answer this

Ann [662]

Answer:

x = 9

Step-by-step explanation:

First step, divide both sides by pi to get rid of it entirely; you should be left with x - 8 = 1 (because when you divide a value by itself, you always get 1, so pi divided by pi gives you 1)

Second step, add 8 to both sides, leaving you with x = 9

4 0

2 years ago

Find the taylor polynomial t3(x) for the function f centered at the number

inysia [295]

Answer:

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3$

Step-by-step explanation:

We are given that

$f(x)=7tan^{-1}(x)$

a=1

$T_n(x)=\sum_{r=0}^{n}\frac{f^r(a)(x-a)^r}{r!}$

Substitute n=3 and a=1

$t_3(x)=f(1)+f'(1)(x-1)+\frac{f''(1)(x-1)^2}{2!}+\frac{f'''(1)(x-1)^3}{3!}$

$f(x)=7tan^{-1}(x)$

$f(1)=7tan^{-1}(1)=7\times \frac{\pi}{4}=\frac{7\pi}{4}$

Where $tan^{-1}(1)=\frac{\pi}{4}$

$f'(x)=\frac{7}{1+x^2}$

Using the formula

$\frac{d(tan^{-1}(x))}{dx}=\frac{1}{1+x^2}$

$f'(1)=\frac{7}{2}$

$f''(x)=\frac{-14x}{(1+x^2)^2}$

$f''(1)=-\frac{7}{2}$

$f''(x)=-14x(x^2+1)^{-2}$

$f'''(x)=-14((x^2+1)^{-2}-4x^2(x^2+1)^{-3}})$

By using the formula

$(uv)'=u'v+v'u$

$f'''(x)=-14(\frac{x^2+1-4x^2}{(1+x^2)^3}$

$f'''(x)=(-14)\frac{-3x^2+1}{(1+x^2)^3}$

$f'''(1)=-14(\frac{-3(1)+1}{2^3})=\frac{7}{2}$

Substitute the values

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{2\times 3\times 2\times 1}(x-1)^3$

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3$

7 0

3 years ago

Louise wants to visit El Paso San Diego Columbus Los Angeles Jacksonville San Antonio Austin and Chicago. If she decides to visi

MakcuM [25]

There are eight cities on the list.

The number of groups of 2 is (8·7)/2 = 28
The number of groups of 3 is (8·7·6)/(3!) = 56
The number of groups of 4 is (8·7·6·5)/(4!) = 70
The number of groups of 5 is (8·7·6·5·4)/(5!) = 56
The number of groups of 6 is (8·7·6·5·4·3)/(6!) = 28
The number of groups of 7 is (8·7·6·5·4·3·2)/(7!) = 8

So there are (28+56+70+56+28+8) = 246 ways to visit "some" of them.

There's only one way to visit "all" of them, and
there's only one way to visit "none" of them.

So, all together, Louise has 248 travel options.
If she decides to visit Chicago, I will show her a good time.

8 0

3 years ago

3 cm<br> 4 cm<br> Find the area.<br> A = 1/2 (a*P)

ss7ja [257]

The answer would be 3:33333

3 0

2 years ago

Angle Pairs Relationships HW

WITCHER [35]

Answer:

Step-by-step explanation:

1. A = 68

B = 112

c = 68

2. A = 127

3. A = 70

B = 55

C = 25

7 0

2 years ago

I am a polygon that has two pairs of opposite sides that are parallel what am I￼￼

I am a polygon that has two pairs of opposite sides that are parallel what am I