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RoseWind [281]
2 years ago
15

When performing forensics on an Apple computer, what operating system are you the most likely to encounter QUIZLET

Computers and Technology
1 answer:
lidiya [134]2 years ago
3 0

When performing forensics on an Apple computer, the operating system are you the most likely to encounter is iOS.

<h3>What is operating system forensics?</h3>

A Operating System Forensics is known to be a method used for the retrieving of any useful information from the Operating System (OS) of the computer or any kind of mobile device.

Note that the reasons for collecting this information is so as to get all the empirical evidence against any kind of perpetrator.

Learn more about operating system from

brainly.com/question/1763761

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What does the following code print?
Crank

Answer:

It throws an error.

the public class needs a name.

like this:

public class G{ public static void main(String[] args) {

   int x=5 , y = 10;

   if (x>5 && y>=2) System.out.println("Class 1");

   else if (x<14 || y>5) System.out.println(" Class 2");

   else System.out.println(" Class 3"); }// end of main

   }

if you give the class a name and format it, you get:

Class 2

Explanation:

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3 years ago
What would be a reason for using a workstation rather than a personal computer?
Pavlova-9 [17]
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4 0
3 years ago
Assume a TCP sender is continuously sending 1,090-byte segments. If a TCP receiver advertises a window size of 5,718 bytes, and
Arturiano [62]

Answer:

for the 5 segments, the utilization is 3.8%

Explanation:

Given the data in the question;

segment size = 1090 bytes

Receiver window size = 5,718 bytes

Link transmission rate or Bandwidth = 26 Mbps = 26 × 10⁶ bps

propagation delay = 22.1 ms

so,

Round trip time = 2 × propagation delay = 2 × 22.1 ms = 44.2 ms

we determine the total segments;

Total segments = Receiver window size / sender segment or segment size

we substitute

Total segments = 5718 bytes / 1090 bytes

Total segments = 5.24587 ≈ 5

Next is the throughput

Throughput = Segment / Round trip

Throughput = 1090 bytes / 44.2 ms

1byte = 8 bits and 1ms = 10⁻³ s

Throughput = ( 1090 × 8 )bits / ( 44.2 × 10⁻³ )s

Throughput = 8720 bits / ( 44.2 × 10⁻³ s )

Throughput = 197.285 × 10³ bps

Now Utilization will be;

Utilization = Throughput / Bandwidth

we substitute

Utilization = ( 197.285 × 10³ bps ) / ( 26 × 10⁶ bps )

Utilization = 0.0076

Utilization is percentage will be ( 0.0076 × 100)% = 0.76%

∴ Over all utilization for the 5 segments will be;

⇒ 5 × 0.76% = 3.8%

Therefore, for the 5 segments, the utilization is 3.8%

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What does the hard disk drive do?
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It stores data and retrieving digital information using one or more rigid rapidly rotating disks (platters) coated in magnetic material
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