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Tamiku [17]
3 years ago
5

The Technology Librarian asks you to find out how many hops it takes to get to the first Wi-Fi kiosk. What Windows command can y

ou use to find this information? What hardware device does each hop represent?
Computers and Technology
1 answer:
V125BC [204]3 years ago
8 0

Answer:

The number of routers arrived in the path of a packet from sender to receiver are called hops. It is term used usually in computer networking.

<u>Command Used to find Hops</u>

In windows command prompt is used to find the number of hops.

1. In Command Prompt type "<em>tracert</em>" after host name and IP address of destination.

<u>Hardware devices Represented by Hop</u>

The main devices that is counted as hop in networking is <em>Router</em>. Nut Sometimes many devices such as <em>switches, repeaters and access points</em> are also count as hops. It depends on the configuration and role of the devices.

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python A pet shop wants to give a discount to its clients if they buy one or more pets. The discount is equal to 20 percent of t
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Answer:

The following are the program in the Python Programming Language.

#define function

def discount(prices, isPet, nItems):

 # declare and initialize variables to 0

 i = 0

 cost = 0

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 item = 0

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 #set the while loop

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     #increament in the variable by 1

     pets += 1

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     #increament in the variable by 1

     item += 1

   #then increment in the variable by 1

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 #and item is greater than equal to 5

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   #then, print the message

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   #set discount of the items

   discount = 0.2 * item_Cost

   # calculate bill after deducting discount

   bill = cost + item_Cost - discount

   #print the bill

   print("Final Bill amount is", bill)

 #otherwise

 else:

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   print("You do not receive any discount")

   #calculate bill without deducting discount

   bill = cost + item_Cost

   #print the final bill

   print("Final Bill amount is", bill)

#set empty list type variables

price = []

pet = []

#set the infinite loop

while True:

 #get input from the user

 sprice = int(input("Enter the price (-1 to quit): "))

 #check that price is not equal to the -1

 if(sprice != -1):

   #add price in the list

   price.append(sprice)

   #ask for choice from the user

   choice = input("Is it a pet (Y / N)? ")

   #check the choice of the user is y or Y

   if(choice == 'Y' or choice == 'y'):

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     pet.append(True)

   #otherwise

   else:

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     pet.append(False)

   print("")

 #break the loop

 else:

   break

#declare variable that store the length

items = len(price)

#call and initialize the variable

discount(price, pet, items)

<u>Output</u>:

Enter the price (-1 to quit): 96

Is it a pet (Y / N)? y

Enter the price (-1 to quit): 69

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 41

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 52

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 96

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 74

Is it a pet (Y / N)? n

Enter the price (-1 to quit): -1

You receive discount

Final Bill amount is 361.6

Explanation:

<u>The following are the description of the program</u>.

  • Firstly, define the function 'discount()' and pass the arguments 'prices', 'isPet' and 'nItems' in its parameter.
  • Then, declare and initialize the variables 'i' to 0, 'item_Cost' to 0
  • , item to 0, 'cost' to 0 and 'pets' to 0.
  • Then, set the while loop to add the price of the items and the cost of the pets.
  • Set the if-else conditional statement to check the pet is greater than equal to 1 and the items are greater than equal to 5 then, set the discount and print the bill after deduction.
  • Otherwise, print the bill without deduction.
  • Finally, set two list type variable then, set the infinite while loop that gets input from the user and check that the variable is not equal to -1 then append the data in the list then again check the user input then append in pet otherwise not append in pet and break the loop. Then, set the variable that stores the length of the price and call the following function by passing arguments in its parameter.
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