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WITCHER [35]
3 years ago
7

Help Me Please.................(5)

Mathematics
1 answer:
just olya [345]3 years ago
6 0
The answer is 5 you’re welcome
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One thing you learned about slopes
AleksandrR [38]

Answer:

one thing that I learned about slope is the rise over run and y2-y1 over x2-x1

Step-by-step explanation:

5 0
3 years ago
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100 POINTS
olga nikolaevna [1]

Answer:

5.2

Step-by-step explanation:

To find the height of the plant after 7 weeks, we need to find out the equation of the line of best fit and plug in 7 for x. We already have our y - intercept, which is 1,  and we have a point on the x axis for which the y coordinate is an integer, (5, 4). Since we already have the y - intercept of +1 we have y = mx + 1. Since this applies to (5,4) we can plug this in to our equation. This is then 4 = 5m + 1. Subtracting 1 from both sides, we get 3 = 5m. Dividing by 5, we receive m = 3/5. Since now we have our slope, we can plug in 7 and find out our answer. Plugging in 7 we receive, y = 3/5 * 7 + 1, which is equal to y = 4.2 + 1. This means that y = 5.2, so 5.2 is our answer.

6 0
3 years ago
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(time limit!) what is the volume below?<br><br>A) 112 <br>B) 224 <br>C) 784 <br>D) 896
Radda [10]
To find a volume of a cylinder we use the following formula:
v = \pi {r}^{2} h
Plug in the values:

v = \pi \times  {8}^{2}  \times 14
Take the square:
v = \pi \times 64 \times 14
Multiply the numbers:
v =896 \pi {m}^{2}
8 0
3 years ago
A triangular prism. The base of a triangular side is shaded. What are the possible shapes of cross sections of this figure? A cr
Alexxandr [17]

Answer:

the first one is triangle and the second one is rectangle

Step-by-step explanation:

i just did it on edge

3 0
3 years ago
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Cubed root x cubed root x2​
Yuki888 [10]

Answer:

Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

Now we need to simplify this problem.

\sqrt[3]{x}\cdot\sqrt[3]{x^2}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}

Apply formula

\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}

so we get:

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

7 0
3 years ago
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