Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
Yes you need to! And you need to be careful not to forgot that when doing your calculations!!
Plug in 2.5 for x and you get
2.5+1 which equals 3.5
Answer:
4
Step-by-step explanation:
hi! let's divide -24 and -6 to simplify this. this is the same answer as 24/6 since two negatives that are divided by each other equal a positive number, and 24 divided by 6 is 4, so the answer is 4.
Answer:
there is not a complete question here ...
is not in a denominator to rationalize
if it were you would multiply the rational expression (the fraction)
by 
the result (in the denominator would end up being "2 -1"
which is 1
Step-by-step explanation:
