For option a, y = 3(4) - 1 = 12 - 1 = 11 [not correct]
For option b, y = 3(2) - 1 = 6 - 1 = 5 [correct]
Therefore option b is a solution to the given equation.
The polynomial as per the given of the problem is f(x)=3x²-21x+30
Find the roots of this polynomial:
x₁=[-b+√b²-4ac)]/2a and x₂ =[-b-√b²-4ac)]/2a
Plug in : x₁ = [21+√(21²-4(3)(30)]/6 = [21+√81}/6 ; x₁ = 5
and x₂ = [21-√(21²-4(3)(30)]/6 = [21-√81]/6 ; x₂ = 2
Remark: I don't understand where did you bring √5 , it should be 5
Answer: Yes it is
Step-by-step explanation:
It also is b=0.5 if you need decimal form.
Answer:
-7/10
Explanation:
Given the expression

We can rewrite the expression as:

The number line showing the location of the two numbers is attached below. Therefore:
Car A Car B
d=rt d = rt
d = ra * 2.4 d = rb 4
ra = rb+22
distances are the same so set the equations equal
ra * 2.4 =rb *4
substitue in for ra
(rb+22) 2.4 =rb *4
distribute
2.4 rb +52.8 = 4 rb
subtract 2.4 rb from each side
52.8 = 1.6 rb
33 = rb
Car b travels at 33 miles per hour
Car a = 33+22
Car a = 55 miles per hour