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Minchanka [31]
2 years ago
9

Solve logx − 1 16 = 4. a) x = 2 b)x = 3 c)x = 4 d)x = 5

Mathematics
1 answer:
White raven [17]2 years ago
8 0

Answer:

3

The Problem:

\log_{x-1}(16)=4.

Step-by-step explanation:

Based on your choices I think you mean:

\log_{x-1}(16)=4.

The equivalent exponential form is:

(x-1)^4=16

Take the fourth of both sides:

(x-1)=\pm 16^\frac{1}{4}

( There is two answer because it was even powered.)

Simplify:

x-1=\pm 2

Add 1 on both sides.

x=1+2=3 \text{ or } x=1-2=-1

Since the base of logarithm can only be postive not including 1, then the answer is just x=3. As x=-1 gives the base as x-1=-1-1=-2.

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Answer:

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Step-by-step explanation:

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We know that

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The solution is: log_{7} \frac{7}{x^{2} }

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