Answer:
- Let p be the population at t be the number of years since 2011. Then,

- The projected population of the high school in 2015=1800
- In <u>2019</u> the population be 1600 students
Step-by-step explanation:
Given: The population at Bishop High School students in 2011 =2000
Also, Every year the population decreases by 50 students which implies the rate of decrease in population is constant.
So, the function is a linear function.
Let p be the population at t be the number of years since 2011.
Then, 
So at t=0, p=2000
In year 2015, t=4, substitute t=4 in the above equation ,we get

Hence, the projected population of the high school in 2015=1800
Now, put p=1600 in the function , we get

Now, 2011+8=2019
Hence, in <u>2019</u> the population be 1600 students
Answer:
the points are (35,30) you may need to search a graph online i used desmos
Step-by-step explanation:
1. x= Jacksons Cups y= Lucius Cups2. x - y= 5 6x + 3y = 300Substitution: 6 (y+5) + 3y = 300 6y + 30 + 3y = 300 9y = 270 dived both by 9 y=30 Sub y for other equation x - 30 = 5 add 30 to both sides x = 35 Answer: (35, 30) Graphing: x- y = 56x+ 3y = 300solve both for y y = x-5 6x + 3y = 300minus 6x from both sides the points are in y = mx + b y= 1x -5 y= -2x + 100 I will also leave the ss of the graph in the comments if you cannot see it My labels for the x-axis is Jacksons cups and y Is luscious cups. Elimination:x - y = 5 6x + 3y = 300 First I manipulated the equations by the following - 6 (x - y = 5 ) 1(6x + 3y = 300 ) -6x + 6y = -30 6x + 3y = 300 The 6 x's cancel and add the y's and real numbers together 9y = 270 dived both by 9 y= 30 Sub y for other equation x - 30 = 6 add 30 to both sides x= 30 The points are (35, 30) The solution is (35,30)They represent how many cups they sold. 35 is Jackson cups and 30 is Lucious's cups
Answer:
Multiply the coordinates of point P by the scale factor 7/4 to get the coordinates of P'.
Given : P(-5,3)
P' (x,y) = P (-5 x 7/4 , 3 x 7/4)
= P(-8.75, 5.25)
Step-by-step explanation:
Step-by-step explanation:
y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1
dy/dx = 12√x
Arc length is:
s = ∫ ds
s = ∫₀¹ √(1 + (dy/dx)²) dx
s = ∫₀¹ √(1 + (12√x)²) dx
s = ∫₀¹ √(1 + 144x) dx
If u = 1 + 144x, then du = 144 dx.
s = 1/144 ∫ √u du
s = 1/144 (⅔ u^(³/₂))
s = 1/216 u^(³/₂)
Substitute back:
s = 1/216 (1 + 144x)^(³/₂)
Evaluate between x=0 and x=1.
s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]
s = 1/216 (145)^(³/₂) − 1/216
s = (145√145 − 1) / 216
Answer:
n = -5
Step-by-step explanation:
n - 4 = 3n + 6
n = 3n + 10
-2n = 10
n = -5