3 years ago

Help please

1 answer:

5 0

Because none of the points on the number line are above 0, we know that the points will be negative.
This eliminates the second and third choices, as they contain positive numbers.
The first point, A, is a number less than -0.5 or -1/2
The first choice matches A with -5/16, which is less than -0.5 or -1/2
Therefore, the fourth choice must be the correct answer.

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The line defined by the equation 2y+3=-(2/3)(x-3) is tangent to the graph of g(x) at x=-3. What is the value of the limit as x a

Otrada [13]

the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
2y+3=-(2/3)(x-3)
6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = $\boxed{ -\frac{1}{3} }$