All categories

3 years ago

Can somebody help me it will mean a lot

Mathematics

1 answer:

tamaranim1 [39]3 years ago

7 0

Angle- side- angle, the triangles are connected and have a line between them (side), & you can see the 2 separate angles amongst them.

You might be interested in

Which is an equation in point-slope form for the given point and slope?

xxMikexx [17]

Hi There!

Solution,

Point Slope Form: y - y1 = m(x - x1)

Now you have a reference equation of what the answer should look like.

By looking at the answer choices you can eliminate A.

Tip: When you have a negative number you are going to add. For Example, if you have -8, you will input x + 8 or y + 8.

Tip 2: When you have a positive number you are going to subtract. For Example, if you have 3 you will input x - 3 or y - 3.

We can eliminate B because its not subtracting 3.

We can also eliminate C because its not adding -8.

The best answer choice is D.

Answer,

y – 3 = 6(x + 8)

I hope you understand, so you can do this in the future on your own.

Hope This Helps :)

4 0

3 years ago

John made $122 in 8 hours.how much did he make per hour

NARA [144]

Answer:

$15.25

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A composition of reflections over parallel lines is the same as a __________. A. translation B. rotation C. glide reflection D.

enyata [817]

Answer: A

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

HELP PLZZ will give brainliest <3

melisa1 [442]

Answer:

Step-by-step explanation:

First question:

You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B}$

$\dfrac{10}{\sin 30^\circ} = \dfrac{40}{\sin B}$

$\dfrac{1}{0.5} = \dfrac{4}{\sin B}$

$\sin B = 2$

The sine function can never equal 2, so there is no triangle in this case.

Answer: no triangle

Second question:

You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.

$\dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

$\dfrac{10}{\sin 63^\circ} = \dfrac{}{\sin C}$

$\sin C = \dfrac{8.9\sin 63^\circ}{10}$

$C = \sin^{-1} \dfrac{8.9\sin 63^\circ}{10}$

$C \approx 52.5^\circ$

One triangle exists for sure. Now we see if there is a second one.

Now we look at the supplement of angle C.

m<C = 52.5°

supplement of angle C: m<C' = 180° - 52.5° = 127.5°

We add the measures of angles B and the supplement of angle C:

m<B + m<C' = 63° + 127.5° = 190.5°

Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.

Answer: one triangle

3 0

4 years ago

I need help please and thank you . I am try to pass this.

Levart [38]

Answer:

11 ≤ n

Explanation:

$\frac{66}{6} = 11$

More than indicates the minimum value, so you use the greater than or equal to.

The above answer is written in reverse, which the exact same result.

I am joyous to assist you anytime.

8 0

3 years ago