Answer:
{x∈R | 
, x∉Z}
Step-by-step explanation:
Given the function y=3tan(2/3x)
We know that tangent is a function that's continuous within it's domain but not continuous on all real numbers
Also, the roots of y=3tan(2/3x) is 
where n is an integer
Note that the domain of the function cannot be within
Therefore, {x∈R | , x∉Z}
Answer:
-4 or 5
Step-by-step explanation:
let number be x
x²-x=20
Rearrange
x²-x-20=0
(x+4)(x-5)=0
Separate
x+4=0, x-5=0
x=-4 or 5
X is greater than or equal to 8
Solution:
(p o q) = p(q(x))
p(q(x)) = 2(x - 3)^2 - 4(x - 3)
======= 2(x - 3)(x - 3) - 4(x - 3)
======= 2(x^2 - 6x + 9) - 4(x -3)
(p o q) = 2x^2 - 10x + 30
(p o q) = 2[x^2 - 5x + 15]
