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hichkok12 [17]
2 years ago
8

Please help im so confused (need asap)

Mathematics
1 answer:
docker41 [41]2 years ago
6 0

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \tt \dashrightarrow \:10 {x}^{2}  - 25x + 15 = 0

\qquad \tt \dashrightarrow \:5(2x {}^{2}  - 5x + 3) = 0

\qquad \tt \dashrightarrow \:2x {}^{2}  - 5x + 3 = 0

\qquad \tt \dashrightarrow \:2x {}^{2}  - 3x - 2x + 3 = 0

\qquad \tt \dashrightarrow \:x(2x - 3) - 1(2x - 3) = 0

\qquad \tt \dashrightarrow \:(x - 1)(2x - 3) = 0

Therefore, the required factors are ~ (x - 1) and (2x - 3)

So, correct choice is B

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Step-by-step explanation:

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Create an equation to solve for x using the trapezoid midsegment formula:
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Answer:

Equation for x:    3x - 6 = \frac{2x - 1 + 25}{2}

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Step-by-step explanation:

The midsegment formula for a trapezoid is

GH = \frac{CD + FE}{2}

3x - 6 = \frac{2x - 1 + 25}{2}

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The principal of a large high school wants to know if students spend more than 1 hour doing homework per night, on average. To i
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Answer:

If we define the random variable X ="time spend by the students doign homework"

And we want to tes t is students spend more than 1 hour doing homework per night, on average (alternative hypothesis), so then the system of hypothesis for this case are:

Null hypothesis: \mu \leq 1

Alternative hypothesis: \mu >1

And they wnat to use a sample size of n = 100 and a significance level of 0.05

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

Solution to the problem

If we define the random variable X ="time spend by the students doign homework"

And we want to tes t is students spend more than 1 hour doing homework per night, on average (alternative hypothesis), so then the system of hypothesis for this case are:

Null hypothesis: \mu \leq 1

Alternative hypothesis: \mu >1

And they wnat to use a sample size of n = 100 and a significance level of 0.05

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This sets up a problem of:

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Step-by-step explanation:

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