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3 years ago

Is (7,26) a solution

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

5 0

Answer:

there isnt no picture or explanation to see if it is

Step-by-step explanation:

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Ulleksa [173]

The answer : x= one half

6 0

3 years ago

(4y+3)-(2y-9)<br> Simplify. Find the difference.

Nadusha1986 [10]

Answer:

2y+12

Hope this helps

Step-by-step explanation:

5 0

3 years ago

Angle W and angle X are congruent. If their sum is 121 degrees, what is the measure of angle X?

Nimfa-mama [501]

< W and < X are congruent....so they are equal.....so if their sum is 121....just divide by 2 for ur answer

121/2 = 60.5.....so < W = 60.5 and < X = 60.5

5 0

3 years ago

The total claim amount for a health insurance policy follows a distribution with density function 1 ( /1000) ( ) 1000 x fx e− =

gizmo_the_mogwai [7]

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is $\mathbf{P(X>1100n) = 0.158655}$

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy is given as :

$f_x(x) = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0$

Thus, the expected total claim amount $\mu$ = 1000

The variance of the total claim amount $\sigma ^2 = 1000^2$

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

$P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})$

$P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})$

$P(X>1100n) = P(Z> \dfrac{10*100}{1000})$

$P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345$

$\mathbf{P(X>1100n) = 0.158655}$

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is $\mathbf{P(X>1100n) = 0.158655}$

4 0

3 years ago

A sphere with a radius of 11 in. Answer in terms of π

Olin [163]

Answer:

3/4πr³

Step-by-step explanation:

solve without solving π

3 0

3 years ago