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3 years ago

The graph below represents two varying sized triangles plotted in the coordinate plane.

1 answer:

4 0

A. triangle is isosceles in several ways. We will show that |AC|=|BC|. We can use the Pythagorean Theorem to check that these both have length 22+32−−−−−−√. In the calculations below M=(3,1) is the midpoint of AB¯¯¯¯¯¯¯¯.

|AC|2|BC|2=|AM|2+|MC|2=22+32=|BM|2+|MC|2=22+32.

We can also observe that to get from A to C we go over (to the right) by two units and then up three units. To get from B to C we go over (to the left) by two units and then up three units. We travel the same distance to get from A or B to C so A and B are equidistant from C. Finally, we can draw the horizontal line of symmetry for △ABC:

hope this helps.....

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Write the equation of the line fully simplified slope-intercept form

harkovskaia [24]

Answer:

$y=\frac{-3}{2}x+8$

Step-by-step explanation:

y=mx+b

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b= 8

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3 years ago

75, 80, 86, 88, 72, 80 Find the Mean of the data set *

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The number of internet paid search ads is increasing as advertisers move away from traditional marketing methods. The equation y

blondinia [14]

Answer: In 2005 the amount spend on internet ads = $74.6 billions.

In 2009 spending on internet search ads will reach $102 billion .

Step-by-step explanation:

Given : The number of internet paid search ads is increasing as advertisers move away from traditional marketing methods.

The equation $y=6.9x+40.1$ can be used to project spending on internet search ads, in billions of dollars, x years after 2000.

To estimate spending on internet ads in 2005.

We need to put x= 5 in the above equation [∵2005-2000=5]

$y=6.9(5)+40.1$

$y=34.5+40.1$

$y=74.6$

i.e. In 2005 the amount spend on internet ads = $74.6 billions.

Put y= 102 in the given equation, we get

$102=6.9x+40.1$

$61.9=6.9x$ [Subtract 40.1 from both sides]

$x=\dfrac{61.9}{6.9}=\dfrac{619}{69}=8.97101449275\approx9$

And 2000+9=2009 [x is the number of years after 2000]

Hence, in 2009 spending on internet search ads will reach $102 billion .

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3 years ago

A study of commuting times reports the travel times to work of a random sample of 20 employed adults in New York State. The mean

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Answer:

The standard error of the mean = 5.14 mins

Step-by-step explanation:

Number of random sample (n) = 20

Mean(X) = 31.25 mins

Standard deviation (α) = 23.7 mins

Standard error of mean =

standard deviation / √sample size

= 23.7/√20

= 23.7/4.4721

= 5.14 mins

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3 years ago

A Situation for y=5x

Tanya [424]

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