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notka56 [123]
2 years ago
6

Quadrilateral wxyz is a paralelogram if w=50 what is wzy

Mathematics
1 answer:
slega [8]2 years ago
8 0
It means different digits.
W=50 would count as one of the digits.
Now you have to figure out what “XYZ” is.
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Complete the table for the given rule.<br><br><br>rule: y=x-4<br><br><br>x:? y:6 0 4
Triss [41]

Answer:

10, 4, 8

Step-by-step explanation:

10 - 4 = 6

4 - 4 = 0

8 - 4 = 4

3 0
3 years ago
D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx
sineoko [7]

Answer:

\frac{1}{2\sqrt{5} }

Step-by-step explanation:

Let, \text{sin}^{-1}(\frac{x}{6}) = y

sin(y) = \frac{x}{6}

\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})

\frac{d}{dx}\text{sin(y)}=\frac{1}{6}

\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx} ---------(1)

\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}

\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}

cos(y) = \sqrt{1-\text{sin}^{2}(y) }

          = \sqrt{1-(\frac{x}{6})^2}

          = \sqrt{1-(\frac{x^2}{36})}

Therefore, from equation (1),

\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

Or \frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

At x = 4,

\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}

\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}

                   =\frac{1}{6\sqrt{\frac{36-16}{36}}}

                   =\frac{1}{6\sqrt{\frac{20}{36} }}

                   =\frac{1}{\sqrt{20}}

                   =\frac{1}{2\sqrt{5}}

4 0
3 years ago
If x = 10, which lines are parallel? Check all that apply.
mart [117]

Answer:

c is parallel to d

Step-by-step explanation:

the degrees need to be equal in order for them to not intersect at any point, if you set x = 10 as given.

5 0
3 years ago
Read 2 more answers
Graph the linear equation. Find three
Karo-lina-s [1.5K]
-3y = -2x -6

Y= 2/3x + 2


When x= 3
Y= 2/3(3) + 2
Y= 2+2 = 4

(3,4)


When x= 6
Y=2/3(6)+2
Y= 4+2 = 6

(6,6)


When x= 12
Y= 2/3(12) + 2
Y= 8+2=10

(12,10)
4 0
3 years ago
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A cylindrical tank has a radius of 15 ft. and a height of 45 ft. How many cubic feet of water can the tank hold?
vladimir1956 [14]
The formula to solve for this would be pi(r^2)xheight. Essentially what this formula does is it takes the are of the base (pi x r^2) and multiplies it by the height of the cylinder to find how many times the base can stack on itself until it reaches the top. This formula of base are times height works for all prisms with two bases. Here are the steps to solve:

1) plug in the values
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2) solve for the base area of one of the circles
- pi(15^2)=225pi

3) multiply the base area by the height
- 225pi x 45 = 10,125pi

4) final answer: the tank can hold 10,125pi cubic feet of water
4 0
3 years ago
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